Two differential current elements, I1dL1 = 3×10–6(&amacr;y) A-m at P1(1, 0, 0) and I2dL2 = 3×10–6(−0.5&amacr;x

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Two differential current elements, I1dL1 = 3×10–6(&amacr;y) A-m at P1(1, 0, 0) and I2dL2 = 3×10–6(−0.5&amacr;x+0.4&amacr;y+0.3&amacr;z) A-m at P2(2, 2, 2) are located in free space. What will be the differential force on I1dL1 by I2dL2?

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Option B: (4.67ā_x+0.67ā_z)×10^–20 N Explanation & Concepts: Practice and solve "Two differential current elements, I1dL1 = 3×10–6(āy) A-m at P1(1, 0, 0) and I2dL2 = 3×10–6(−0..." for Electrical - Electromagnetics Field Theory . The correct answer is Option B: (4.67āx+0.67āz)×10–20 N. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.

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Option A: (−1.33&amacr;x+0.33&amacr;y−2.67&amacr;z)×10–20 N

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Option C: (−1.33&amacr;x+0.33&amacr;y−2.67&amacr;z) N

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Option D: (4.67&amacr;x+0.67&amacr;z) N

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