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What happens when sodium hydroxide reacts with copper (II) sulfate solution?
No reaction occurs.
Sodium sulfate is formed.
Copper metal is deposited.
Copper(II) hydroxide precipitates.
Copper(II) hydroxide precipitates.
When sodium hydroxide solution is added to copper(II) sulfate solution, a double displacement reaction takes place. A pale blue precipitate of copper(II) hydroxide is formed along with sodium sulfate remaining in the solution.
When sodium hydroxide solution is added to copper(II) sulfate solution, a double displacement reaction takes place. A pale blue precipitate of copper(II) hydroxide is formed along with sodium sulfate remaining in the solution.
Think of it like mixing two pairs of dance partners in a room: when the copper ion pairs up with hydroxide, they form a solid bond that makes them sit down (precipitate) out of the liquid dance floor immediately.
Blue Precipitate = Copper Hydroxide (BPC - Blue Pale Copper)
2NaOH(aq)тАЛ+CuSO4(aq)тАЛтЖТCu(OH)2(s)тАЛтЖУ+Na2тАЛSO4(aq)тАЛ тАФ Molecular equation showing precipitation of copper(II) hydroxide
Cu(aq)2+тАЛ+2OH(aq)тИТтАЛтЖТCu(OH)2(s)тАЛ тАФ Net ionic equation for copper(II) hydroxide precipitation
In this double displacement (precipitation) reaction, the aqueous Cu2+ ions from copper(II) sulfate combine with OHтИТ ions from sodium hydroxide to form insoluble copper(II) hydroxide, Cu(OH)2тАЛ. The ionic equation for this reaction is Cu(aq)2+тАЛ+2OH(aq)тИТтАЛтЖТCu(OH)2(s)тАЛ.
Reaction type: Double displacement and precipitation reaction.
Copper(II) hydroxide forms as a characteristic pale blue precipitate.
Excess sodium hydroxide does not dissolve the pale blue precipitate of Cu(OH)2тАЛ, unlike zinc hydroxide.
Qualitative chemical analysis to test for the presence of Cu2+ cations in a solution.
Preparation of copper oxide upon heating the precipitated Cu(OH)2тАЛ.
Option A is incorrect because a double displacement reaction clearly takes place.
Option B is incorrect because although sodium sulfate is formed, it remains dissolved in aqueous solution and does not precipitate.
Option C is incorrect because copper metal is not deposited; metal displacement requires a more reactive free metal like iron or zinc.
Heating the resulting pale blue Cu(OH)2тАЛ precipitate turns it into black copper(II) oxide (CuO).
D is correct тАФ Sodium hydroxide reacts with copper(II) sulfate solution to yield an insoluble pale blue precipitate of copper(II) hydroxide.
For competitive exams, remember that Cu2+ forms a pale blue precipitate of Cu(OH)2тАЛ with NaOH, while Fe2+ gives a dirty green precipitate of Fe(OH)2тАЛ and Fe3+ gives a reddish-brown precipitate of Fe(OH)3тАЛ.