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What is the expanded form of (4x + 3y + 5z)2?
16x2+9y2+25z2+24xy+30yz+40xz
16x2+9y2+25z2+12xy+15yz+20xz
8x2+6y2+10z2+24xy+30yz+40xz
16x2+9y2+25z2+24xy+30yz+20xz
16x2+9y2+25z2+24xy+30yz+40xz
Use the standard algebraic identity for the square of a trinomial and compute the cross-terms quickly by multiplying coefficients pairwise.
Expression to expand: (4x+3y+5z)2
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
Use the standard algebraic identity for the square of a trinomial and compute the cross-terms quickly by multiplying coefficients pairwise.
Forgetting to multiply the cross-terms by 2 or making sign errors while squaring negative terms (if any).
Identify the standard identity
To expand the square of a trinomial with three terms a, b, and c, we use the identity for (a+b+c)2.
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
Substitute the values
Here, let a=4x, b=3y, and c=5z. Substitute these into the identity.
(4x+3y+5z)2=(4x)2+(3y)2+(5z)2+2(4x)(3y)+2(3y)(5z)+2(5z)(4x)
Simplify each term
Square each individual term and compute the product for each cross-term: (4x)2=16x2, (3y)2=9y2, (5z)2=25z2.
16x2+9y2+25z2+2(12xy)+2(15yz)+2(20xz)
Final expansion
Multiply the cross-terms by 2 to get the final expanded expression.
16x2+9y2+25z2+24xy+30yz+40xz
A is correct because expanding (4x+3y+5z)2 using the algebraic identity yields 16x2+9y2+25z2+24xy+30yz+40xz.
Trinomial expansions are frequently tested in algebraic simplification and polynomial factorization questions in CBT-1 exams.