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ElectricalMachine
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What is the expression for force in a current carrying conductor?

A

F=Kr2F = \frac{K}{r^2}F=r2KтАЛ

B

F=Kqr2F = \frac{Kq}{r^2}F=r2KqтАЛ

C

F=Kq1q2r2F = \frac{K q_1 q_2}{r^2}F=r2Kq1тАЛq2тАЛтАЛ

D

F=Kq1q2rF = \frac{K q_1 q_2}{r}F=rKq1тАЛq2тАЛтАЛ

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalMachine
Option C

F=Kq1q2r2F = \frac{K q_1 q_2}{r^2}F=r2Kq1тАЛq2тАЛтАЛ

Quick Summary:

The force of interaction between two point charges is governed by Coulomb's Law, which states that the force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Although the question title references a 'current carrying conductor', the provided options define the electrostatic force between two point charges.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

The force of interaction between two point charges is governed by Coulomb's Law, which states that the force is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance between them. Although the question title references a 'current carrying conductor', the provided options define the electrostatic force between two point charges.

ЁЯФв Key Formulas

F=Kq1q2r2F = \frac{K q_1 q_2}{r^2}F=r2Kq1тАЛq2тАЛтАЛ тАФ Coulomb's Law for electrostatic force

K=14╧А╧╡0K = \frac{1}{4 \pi \epsilon_0}K=4╧А╧╡0тАЛ1тАЛ тАФ Coulomb's constant in vacuum

тЪЩя╕П Working Principle

The principle relies on the inverse-square law for electric fields created by stationary charges. When two point charges q1q_1q1тАЛ and q2q_2q2тАЛ are placed at a distance rrr in a medium, the electrostatic force FFF acts along the line joining them, with KKK being the Coulomb's constant.

ЁЯУМ Key Points
  • тЦ╕

    Electrostatic force is a vector quantity.

  • тЦ╕

    The force is attractive for unlike charges and repulsive for like charges.

  • тЦ╕

    Coulomb's law is valid for point charges at rest.

тЬЕ Advantages
  • тЦ╕

    Provides a simple mathematical model for point interactions.

  • тЦ╕

    Fundamental basis for understanding electric fields.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Not applicable to distributed charges without integration.

  • тЦ╕

    Does not account for relativistic effects at high speeds.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Calculation of field intensities.

  • тЦ╕

    Design of electrostatic sensors and MEMS devices.

ЁЯУД Additional Information
  • тЦ╕

    Note: The question text mentions a 'current carrying conductor' but the options provided are strictly for electrostatic force. If the question intended magnetic force on a conductor, the formula would involve F=I(L├ЧB)F = I(L \times B)F=I(L├ЧB).

  • тЦ╕

    Options A, B, and D are dimensionally incorrect for the electrostatic force law.

ЁЯУК Diagram / Illustration
Coulomb's Law FormulaF = K qтВБ qтВВr┬▓
тЬЕ

C is correct тАФ The electrostatic force between two point charges is given by Coulomb's Law, defined as F=Kq1q2r2F = \frac{K q_1 q_2}{r^2}F=r2Kq1тАЛq2тАЛтАЛ.

Core Concepts Used
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Coulomb's Law Inverse Square Law Electrostatics
ЁЯТб EXAM TIP

Always verify if the question asks for electrostatic force (Coulomb's Law) or electromagnetic force (Lorentz Force) before applying the formula.

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