What will be the discharge of a single-acting pump if it has o... | Technical Ability MCQ | Examoogle

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What will be the discharge of a single-acting pump if it has one cylinder of area 0.5 m 2 and stroke of length 20 cm and if the pump has 180 rpm of speed?

0.1 m³/s

0.3 m³/s

0.2 m³/s

0.25 m³/s

Correct Answer

⚙️ TE • Technical Concept & PrincipleTechnical AbilityHydraulic Machines

Option B

0.3 m³/s

Quick Summary:

The discharge of a single-acting reciprocating pump is calculated as the product of the cylinder area, stroke length, and the number of strokes per second. Given the area $A = 0.5 \text{ m}^2$ , stroke length $L = 0.2 \text{ m}$ , and speed $N = 180 \text{ rpm}$ , the discharge $Q$ is determined by $Q = \frac{A \times L \times N}{60}$ .

⚙️TETechnical SolutionConcept & Principle

💡 Explanation

🔢 Key Formulas

$Q = \frac{A \times L \times N}{60}$ — Discharge of a single-acting reciprocating pump in $\text{m}^3/\text{s}$

$V_s = A \times L$ — Swept volume per stroke in $\text{m}^3$

⚙️ Working Principle

In a single-acting reciprocating pump, the piston performs a suction stroke to draw fluid into the cylinder and a delivery stroke to push it out. Only one delivery stroke occurs per revolution of the crankshaft, meaning the volume displaced per revolution is the swept volume $V_s = A \times L$ . The total discharge is the volume displaced per minute divided by 60 to convert units to seconds.

📌 Key Points

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Area $A = 0.5 \text{ m}^2$
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Stroke length $L = 0.2 \text{ m}$
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Rotational speed $N = 180 \text{ rpm}$
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Calculation: $Q = \frac{0.5 \times 0.2 \times 180}{60} = 0.5 \times 0.2 \times 3 = 0.3 \text{ m}^3/\text{s}$

✅ Advantages

▸
Capable of producing high delivery heads
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Maintains constant discharge regardless of head variations

❌ Disadvantages / Limitations

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High maintenance due to reciprocating parts
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Fluctuating flow rate compared to centrifugal pumps

🛠️ Applications / Uses

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High-pressure hydraulic systems
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Small-scale water pumping where high pressure is required

📄 Additional Information

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The discharge value is $0.3 \text{ m}^3/\text{s}$ , which matches Option B.
▸
For double-acting pumps, the formula is modified to $Q = \frac{2 \times A \times L \times N}{60}$ as two delivery strokes occur per revolution.

📊 Diagram / Illustration

✅

B is correct — The discharge is calculated as $\frac{0.5 \times 0.2 \times 180}{60} = 0.3 \text{ m}^3/\text{s}$ .

Core Concepts Used

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Reciprocating Pump Dynamics Swept Volume Discharge Calculation

💡 EXAM TIP

Always ensure the rotational speed unit is converted from rpm to strokes per second (divide by 60) before final multiplication with geometric parameters.

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