Join 60,000+ competitive exam aspirants
What will be the magnitude of the force exerted on the charge by the fields B = −3āx+4āy+6āz mT and E = −3āx+4āy+6āz kV/m when a charge of 18 nC is moving with a velocity of 5×10⁶ m/s in the direction of 0.6āx+0.75āy+0.3āz.
660 μN
140 μN
670 μN
810 μN
670 μN
Practice and solve "What will be the magnitude of the force exerted on the charge by the fields B = −3āx+4āy..." for Electrical - Electromagnetics Field Theory . The correct answer is Option C: 670 μN. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.
Option **(c) **