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What will be the value of Vemf for a material having a flux linkage of 2t² at time t = 1second?
2 Volt
4 Volt
8 Volt
16 Volt
4 Volt
Given: Flux linkage (lambda)=2t2, Time t = 1 second
Flux linkage (lambda)=2t2, Time t = 1 second
Vemf=−dtdλ
Identify Faraday's Law
According to Faraday's Law of electromagnetic induction, the induced electromotive force (Vemf) is defined as the negative rate of change of magnetic flux linkage.
Vemf=−dtdλ
Differentiate Flux Linkage
Given flux linkage λ=2t2. Differentiating this with respect to time t gives:
dtdλ=dtd(2t2)=4t
Calculate Magnitude at t = 1
Substitute t=1 second into the derivative expression to find the magnitude of the EMF.
∣Vemf∣=∣4(1)∣=4 Volts
B is correct because the magnitude of the EMF induced in the material is calculated by taking the derivative of the flux linkage 2t2 with respect to time, which yields 4t, and evaluating it at t=1 second results in 4 Volts.
This concept is fundamental to Lenz's Law; remember that the negative sign represents the direction of the induced EMF opposing the change in magnetic flux, common in Transformer and Generator analysis.