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ElectricalPower System
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When a line-to-ground fault occurs, the current in a faulted phase is 100 A. The zero sequence current in this case will be

A

Zero

B

33.3 A

C

66.6 A

D

100 A

Correct Answer

⚙️ TE • Technical Direct FormulaElectricalPower System
Option B

33.3 A

Quick Summary:

Given: Fault current in the faulted phase (If) = 100 A.

📐MAMath SolutionDirect Formula
📋 Given

Fault current in the faulted phase (If) = 100 A.

🔢 Formula Used

I0=13IfI_0 = \frac{1}{3} I_fI0​=31​If​

🔢 Step-by-Step Solution
1

Identify Fault Condition

In a single line-to-ground (SLG) fault, the symmetrical component theory states that the phase current is the sum of its positive, negative, and zero sequence components.

If=Ia1+Ia2+Ia0I_f = I_{a1} + I_{a2} + I_{a0}If​=Ia1​+Ia2​+Ia0​

2

Apply Sequence Component Relationship

For an SLG fault, the sequence currents are equal: Ia1=Ia2=Ia0I_{a1} = I_{a2} = I_{a0}Ia1​=Ia2​=Ia0​. Therefore, the total fault current is three times the zero sequence current.

If=3Ia0I_f = 3 I_{a0}If​=3Ia0​

3

Calculate Zero Sequence Current

Given If=100I_f = 100If​=100 A, we rearrange the formula to find Ia0I_{a0}Ia0​.

Ia0=1003≈33.33 AI_{a0} = \frac{100}{3} \approx 33.33 \text{ A}Ia0​=3100​≈33.33 A

✅

B is correct because in a single line-to-ground fault, the zero sequence current is exactly one-third of the total fault current flowing through the faulted phase.

Core Concepts Used
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Symmetrical Components Unsymmetrical Faults Sequence Networks
💡 EXAM TIP

This relationship holds specifically for SLG faults; for Line-to-Line (LL) faults, the zero sequence current is zero, which is a common trick question in competitive exams.

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