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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ElectricalPower System
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When earth fault occurs, healthy phase voltage increased to

A

times

B

times

C

1.731.731.73 times

D

times

Correct Answer

Concept & PrincipleElectricalPower System
Option A

times

Quick Summary: In an ungrounded or isolated neutral system, when a single line-to-ground (SLG) fault occurs on one phase, the voltage of the healthy phases with respect to the ground increases from phase voltage ($V_{ph}$) to line voltage ($V_L$). Since the line voltage is $\sqrt{3}$ times the phase voltage, the potential of the healthy phases relative to ground rises by approximately 1.732 times.

💡 Explanation

In an ungrounded or isolated neutral system, when a single line-to-ground (SLG) fault occurs on one phase, the voltage of the healthy phases with respect to the ground increases from phase voltage (VphV_{ph}Vph​) to line voltage (VLV_LVL​). Since the line voltage is 3\sqrt{3}3​ times the phase voltage, the potential of the healthy phases relative to ground rises by approximately 1.732 times.

🔢 Key Formulas

VL=3×VphV_{L} = \sqrt{3} \times V_{ph}VL​=3​×Vph​ — Relationship between line and phase voltage

Vhealthy=3×VphV_{healthy} = \sqrt{3} \times V_{ph}Vhealthy​=3​×Vph​ — Healthy phase voltage under SLG fault in ungrounded system

⚙️ Working Principle

During normal operation, the voltage of each phase relative to the ground is Vph=VLine3V_{ph} = \frac{V_{Line}}{\sqrt{3}}Vph​=3​VLine​​. When one phase is shorted to the ground, the fault phase potential becomes 0V relative to ground. Because the source neutral remains floating, the system neutral shifts, forcing the healthy phases to maintain their potential difference relative to each other (which is VLV_LVL​). Consequently, the healthy phase voltage vectors relative to ground rotate such that their magnitude equals the line-to-line voltage.

📌 Key Points
  • ▸

    The 1.73 times increase is specific to isolated or ungrounded neutral systems.

  • ▸

    The fault phase voltage drops to nearly zero potential relative to the earth.

  • ▸

    This phenomenon causes increased stress on the insulation of the healthy phases.

  • ▸

    System operators must use proper surge arresters or grounding transformers to mitigate this rise.

✅ Advantages
  • ▸

    Allows continued operation of the system during a single earth fault

  • ▸

    Provides high reliability for sensitive industrial loads

❌ Disadvantages / Limitations
  • ▸

    Increases insulation stress on healthy phases

  • ▸

    Potential for arcing ground faults if not cleared

🛠️ Applications / Uses
  • ▸

    Isolated neutral distribution systems

  • ▸

    Delta-connected medium voltage networks

📄 Additional Information
  • ▸

    In effectively grounded systems, the voltage rise on healthy phases is significantly lower (typically 0.8 to 1.4 p.u. depending on the grounding coefficient).

  • ▸

    Option 2 times, 3 times, and 1.5 times are incorrect as they do not represent the standard trigonometric relationship derived from the phasor geometry of a 3-phase system.

📊 Diagram / Illustration
Healthy Phase Voltage Rise
Vfaulted=VL=3×VphV_{faulted} = V_L = \sqrt{3} \times V_{ph}Vfaulted​=VL​=3​×Vph​
Ratio=3≈1.732Ratio = \sqrt{3} \approx 1.732Ratio=3​≈1.732
✅

C is correct — The healthy phase voltage rises to 1.73 times its normal value because it effectively takes on the line-to-line potential relative to the grounded faulted phase.

Core Concepts Used
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Unbalanced Faults Phasor Analysis System Grounding
💡 EXAM TIP

Always remember that in an isolated neutral system, the vector sum of voltages is zero. If one phase is grounded, the remaining two form a line-to-line triangle with the ground, making the voltage relative to ground equal to the line voltage.

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