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ElectricalElectric Drives
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When the ratio of back E.MF to applied voltage is ___ than the mechanical power develop by the shunt generator is maximum?

A

1

B

5

C

2

D

3

Correct Answer

Concept & PrincipleElectricalElectric Drives
Option B

5

Quick Summary: In a DC motor, the mechanical power developed is maximum when the ratio of back EMF ($E_b$) to applied voltage ($V$) is 0.5. This condition corresponds to the point where the current drawn is half of the stall current (short circuit current), effectively delivering maximum power to the load.

💡 Explanation

In a DC motor, the mechanical power developed is maximum when the ratio of back EMF (EbE_bEb​) to applied voltage (VVV) is 0.5. This condition corresponds to the point where the current drawn is half of the stall current (short circuit current), effectively delivering maximum power to the load.

🔢 Key Formulas

Pm=EbIaP_m = E_b I_aPm​=Eb​Ia​ — Mechanical power developed

EbV=0.5\frac{E_b}{V} = 0.5VEb​​=0.5 — Ratio for maximum power

⚙️ Working Principle

The mechanical power developed (PmP_mPm​) in a DC motor is given by Pm=Eb⋅IaP_m = E_b \cdot I_aPm​=Eb​⋅Ia​. Substituting Ia=V−EbRaI_a = \frac{V - E_b}{R_a}Ia​=Ra​V−Eb​​, we get Pm=Eb⋅V−EbRa=V⋅Eb−Eb2RaP_m = E_b \cdot \frac{V - E_b}{R_a} = \frac{V \cdot E_b - E_b^2}{R_a}Pm​=Eb​⋅Ra​V−Eb​​=Ra​V⋅Eb​−Eb2​​. To find the maximum, we set the derivative dPmdEb=0\frac{dP_m}{dE_b} = 0dEb​dPm​​=0, which yields V−2Eb=0V - 2E_b = 0V−2Eb​=0, or EbV=0.5\frac{E_b}{V} = 0.5VEb​​=0.5.

📌 Key Points
  • ▸

    The maximum power condition assumes constant supply voltage VVV and armature resistance RaR_aRa​.

  • ▸

    At maximum power, the efficiency of the DC motor is typically 50% as half the power is lost in the armature resistance.

  • ▸

    This condition is rarely used in continuous operation due to high current and heat dissipation limits.

✅ Advantages
  • ▸

    Useful in understanding power transfer limitations

  • ▸

    Establishes a fundamental limit for electrical machine torque analysis

❌ Disadvantages / Limitations
  • ▸

    Motor efficiency drops to 50% at maximum power transfer

  • ▸

    High currents lead to overheating and potential demagnetization

🛠️ Applications / Uses
  • ▸

    DC drive sizing

  • ▸

    Electromechanical system performance optimization

📄 Additional Information
  • ▸

    The condition EbV=0.5\frac{E_b}{V} = 0.5VEb​​=0.5 is often termed the 'Maximum Power Transfer Theorem' application in electrical machines.

  • ▸

    Option B is correct because the differentiation of the power equation with respect to EMF leads to 0.5.

📊 Diagram / Illustration
Max Power ConditionE♭ = 0.5V
EbV=0.5(E_b / V) = 0.5VEb​​=0.5
✅

B is correct — Mechanical power developed in a DC motor is maximum when the back EMF is exactly half of the applied terminal voltage.

Core Concepts Used
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Back EMF Maximum Power Transfer Armature circuit resistance
💡 EXAM TIP

Always remember that maximum power transfer in DC machines happens at 50% efficiency, which is a major constraint in practical motor design.

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