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Which is the smallest number that is exactly divisible by 12, 15, and 20?
60
90
120
180
60
Check the options starting from the smallest. Since 60 is divisible by 12, 15, and 20 (60/12=5, 60/15=4, 60/20=3), it is the smallest candidate.
We need to find the smallest number exactly divisible by the numbers 12, 15, and 20.
LCM(a,b,c)=Product of highest powers of all prime factors present in the numbers
Check the options starting from the smallest. Since 60 is divisible by 12, 15, and 20 (60/12=5, 60/15=4, 60/20=3), it is the smallest candidate.
Students often calculate the Greatest Common Divisor (HCF) instead of the Least Common Multiple (LCM), leading to incorrect answers like 1 or 5.
Prime Factorization
Express each number as a product of its prime factors: 12=22×31, 15=31×51, and 20=22×51.
12=22×3,15=3×5,20=22×5
Apply LCM rule
Identify the highest power of each prime factor present in the factorization: 22, 31, and 51.
LCM=22×31×51
Final Calculation
Multiply the identified factors to get the result: 4×3×5=60.
LCM=4×3×5=60
A is correct because 60 is the smallest positive integer that is a multiple of 12, 15, and 20.
This concept is fundamental for solving problems related to circular tracks, bell ringing intervals, and traffic light synchronization in aptitude tests.