Examoogle
ExamsTest SeriesCBATRank CheckPrevious Year PapersPassBook StoreMy BooksAI Tutor
ЁЯЫТ0
рдЕA
Examoogle

India's most trusted platform for competitive exam PDF books. Expert-authored, watermark-protected, instant access.

Exams & Practice
All Exams & SyllabusMock Test SeriesPrevious Year PapersPractice Questions (MCQs)Recruitment Notifications
Quick Links
Examoogle AI TutorExam NewsBook StoreMy BooksLogin / Sign Up
Support
About UsRefund PolicyPrivacy PolicyTerms of UseContact Us
┬й 2026 Examoogle. India's #1 competitive exam AI tutor.
ЁЯФТ SSL SecuredЁЯУ▒ UPI AcceptedЁЯз╛ GST Invoice
Examoogle

Join 60,000+ competitive exam aspirants

or with email
By continuing, you agree to ourTerms of Service&Privacy Policy
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Back to Practice Questions
ElectricalMachine
PrevNext

Which of the following formulas is used to find the value of different section resistance?

A

rn=RnтИТRn+1r_n = R_n - R_{n+1}rnтАЛ=RnтАЛтИТRn+1тАЛ

B

rn=╬▒nтИТ1r1r_n = \alpha^{n-1} r_1rnтАЛ=╬▒nтИТ1r1тАЛ

C

rn=╬▒rnтИТ1r_n = \alpha r_{n-1}rnтАЛ=╬▒rnтИТ1тАЛ

D

All of these

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleElectricalMachine
Option D

All of these

Quick Summary:

In DC motor starter design (such as a resistance starter), the total starting resistance is divided into nnn sections to limit the armature starting current within safe limits. The resistance values of these individual sections form a geometric progression with a constant ratio ╬▒\alpha╬▒. Consequently, all the listed equations are mathematically equivalent expressions used to calculate the resistance of the nnn-th section.

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

In DC motor starter design (such as a resistance starter), the total starting resistance is divided into nnn sections to limit the armature starting current within safe limits. The resistance values of these individual sections form a geometric progression with a constant ratio ╬▒\alpha╬▒. Consequently, all the listed equations are mathematically equivalent expressions used to calculate the resistance of the nnn-th section.

ЁЯФв Key Formulas

rn=RnтИТRn+1r_n = R_n - R_{n+1}rnтАЛ=RnтАЛтИТRn+1тАЛ тАФ Resistance of the nnn-th section as difference of total circuit resistances

rn=╬▒тЛЕrnтИТ1r_n = \alpha \cdot r_{n-1}rnтАЛ=╬▒тЛЕrnтИТ1тАЛ тАФ Recursive relationship between adjacent section resistances

rn=╬▒nтИТ1тЛЕr1r_n = \alpha^{n-1} \cdot r_1rnтАЛ=╬▒nтИТ1тЛЕr1тАЛ тАФ Section resistance in terms of the first section resistance r1r_1r1тАЛ

╬▒=(RmR1)1nтИТ1=IminImax\alpha = \left(\frac{R_m}{R_1}\right)^{\frac{1}{n-1}} = \frac{I_{min}}{I_{max}}╬▒=(R1тАЛRmтАЛтАЛ)nтИТ11тАЛ=ImaxтАЛIminтАЛтАЛ тАФ Resistance ratio constant for nnn-step starter

тЪЩя╕П Working Principle

When starting a DC motor, starting resistance is cut out in steps as the motor speeds up and builds back EMF (EbE_bEbтАЛ). For equal peak current spikes at each step, the total circuit resistances after each step (R1,R2,тАж,RnR_1, R_2, \dots, R_nR1тАЛ,R2тАЛ,тАж,RnтАЛ) form a geometric progression where Rn+1=╬▒RnR_{n+1} = \alpha R_nRn+1тАЛ=╬▒RnтАЛ or ╬▒=Rn+1/Rn<1\alpha = R_{n+1}/R_n < 1╬▒=Rn+1тАЛ/RnтАЛ<1. The section resistance rnr_nrnтАЛ cut out in the nnn-th step is the difference between consecutive total resistances RnтИТRn+1R_n - R_{n+1}RnтАЛтИТRn+1тАЛ, which can also be expressed as rn=╬▒rnтИТ1r_n = \alpha r_{n-1}rnтАЛ=╬▒rnтИТ1тАЛ or rn=╬▒nтИТ1r1r_n = \alpha^{n-1} r_1rnтАЛ=╬▒nтИТ1r1тАЛ.

ЁЯУМ Key Points
  • тЦ╕

    The resistances of individual sections r1,r2,r3,тАж,rnr_1, r_2, r_3, \dots, r_nr1тАЛ,r2тАЛ,r3тАЛ,тАж,rnтАЛ decrease in a geometric progression.

  • тЦ╕

    ╬▒\alpha╬▒ is the ratio of minimum starting current (IminI_{min}IminтАЛ) to maximum starting current (ImaxI_{max}ImaxтАЛ), where ╬▒<1\alpha < 1╬▒<1.

  • тЦ╕

    RnR_nRnтАЛ represents the total circuit resistance when the stud is on the nnn-th step.

тЬЕ Advantages
  • тЦ╕

    Ensures equal upper current limits (ImaxI_{max}ImaxтАЛ) and lower current limits (IminI_{min}IminтАЛ) during each step of starting.

  • тЦ╕

    Provides smooth acceleration of the DC motor without excessive current spikes.

тЭМ Disadvantages / Limitations
  • тЦ╕

    Requires precise calculation of non-uniform resistance steps.

  • тЦ╕

    Power loss occurs across the external resistance during the starting phase.

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Design of multi-step resistance starters for DC shunt and series motors.

  • тЦ╕

    Rotor resistance starters for 3-phase slip ring induction motors.

ЁЯУД Additional Information
  • тЦ╕

    Option A is correct because rnr_nrnтАЛ is directly defined as the difference between the total circuit resistance at step nnn (RnR_nRnтАЛ) and step n+1n+1n+1 (Rn+1R_{n+1}Rn+1тАЛ).

  • тЦ╕

    Option B and Option C are correct because section resistances decrease in GP with common ratio ╬▒\alpha╬▒, so rn=╬▒rnтИТ1=╬▒nтИТ1r1r_n = \alpha r_{n-1} = \alpha^{n-1} r_1rnтАЛ=╬▒rnтИТ1тАЛ=╬▒nтИТ1r1тАЛ.

  • тЦ╕

    Hence, Option D ('All of these') is the correct choice.

ЁЯУК Diagram / Illustration
Section Resistance Formulas in Starters1. Difference Form:rтВЩ = RтВЩ - RтВЩтВКтВБ2. Geometric Progression:rтВЩ = ╬▒тБ┐тБ╗┬╣ ┬╖ rтВБ3. Recursive Form:rтВЩ = ╬▒ ┬╖ rтВЩтВЛтВБ
тЬЕ

D is correct тАФ all three given expressions are valid mathematical relations used for determining the value of section resistance in a DC motor starter.

Core Concepts Used
Click any tag to open in AI Tutor
DC Motor Starters Starter Resistance Grading Geometric Progression in Resistance Steps
ЁЯТб EXAM TIP

Remember that for a starter with nnn sections (and n+1n+1n+1 studs), the resistance ratio ╬▒=IminImax=(RarmatureR1)1n\alpha = \frac{I_{min}}{I_{max}} = \left(\frac{R_{armature}}{R_1}\right)^{\frac{1}{n}}╬▒=ImaxтАЛIminтАЛтАЛ=(R1тАЛRarmatureтАЛтАЛ)n1тАЛ. Use this relation directly in numerical problems to find the number of steps or resistance per section.

Related Questions

ElectricalMachine
In the design of single-phase induction motor. The Length of air gap is given by
ElectricalMachine
In the design of single-phase induction motor. The length of a mean turn of each coil per pole,
ElectricalMachine
In the design of single-phase induction motor. The flux density in the stator core is given by
ElectricalMachine
In the design of single-phase induction motor. The maximum flux density in stator core is ____________ for and the normal range is _________
ElectricalMachine
In the design of single-phase induction motor. The flux density in stator teeth is given by

Discussion (0)

Loading discussion...
PrevNext