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CivilSoil Mechanics
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Which of the following is coulombтАЩs strength equation?

A

S=C+tanтБб╧ХS = C + \tan \phiS=C+tan╧Х

B

C=S+╧ГtanтБб╧ХC = S + \sigma \tan \phiC=S+╧Гtan╧Х

C

S=C+╧ГtanтБб╧ХS = C + \sigma \tan \phiS=C+╧Гtan╧Х

D

S=tanтБб╧ХS = \tan \phiS=tan╧Х

Correct Answer

тЪЩя╕П TE тАв Technical Concept & PrincipleCivilSoil Mechanics
Option C

S=C+╧ГtanтБб╧ХS = C + \sigma \tan \phiS=C+╧Гtan╧Х

Quick Summary:

Coulomb's Law (or the Mohr-Coulomb failure criterion) states that the shear strength of a soil at failure is a linear function of the normal stress acting on the failure plane. It is expressed as the sum of cohesion (CCC) and the product of normal stress (╧Г\sigma╧Г) and the tangent of the internal angle of friction (╧Х\phi╧Х).

тЪЩя╕ПTETechnical SolutionConcept & Principle
ЁЯТб Explanation

Coulomb's Law (or the Mohr-Coulomb failure criterion) states that the shear strength of a soil at failure is a linear function of the normal stress acting on the failure plane. It is expressed as the sum of cohesion (CCC) and the product of normal stress (╧Г\sigma╧Г) and the tangent of the internal angle of friction (╧Х\phi╧Х).

ЁЯФв Key Formulas

S=C+╧ГtanтБб╧ХS = C + \sigma \tan \phiS=C+╧Гtan╧Х тАФ The Mohr-Coulomb failure criterion equation

тЪЩя╕П Working Principle

The shear strength is composed of two components: the intrinsic cohesion (CCC) which represents the bonding between soil particles, and the frictional component (sigmatanтБб╧Хsigma \tan \phisigmatan╧Х) which arises from the intergranular contact and mechanical interlocking of soil particles under normal stress. As normal stress increases, the frictional resistance increases proportionally until failure occurs.

ЁЯУМ Key Points
  • тЦ╕

    Cohesion (CCC) is the shear strength at zero normal stress.

  • тЦ╕

    The internal angle of friction (╧Х\phi╧Х) represents the shear strength contributed by inter-particle friction.

  • тЦ╕

    The equation assumes a linear relationship between shear strength and normal stress.

  • тЦ╕

    This criterion is foundational for stability analysis of slopes and earth retaining structures.

тЬЕ Advantages
  • тЦ╕

    Simple mathematical model for complex soil behavior

  • тЦ╕

    Easily derived from standard laboratory tests like Direct Shear or Triaxial tests

тЭМ Disadvantages / Limitations
  • тЦ╕

    Assumes linear behavior which may not hold for all soil types at high pressures

  • тЦ╕

    Does not account for pore water pressure unless effective stress is explicitly considered

ЁЯЫая╕П Applications / Uses
  • тЦ╕

    Bearing capacity analysis of foundations

  • тЦ╕

    Slope stability assessment

  • тЦ╕

    Lateral earth pressure calculations in retaining walls

ЁЯУД Additional Information
  • тЦ╕

    In terms of effective stress, the equation is expressed as s=cтА▓+╧ГтА▓tanтБб╧ХтА▓s = c' + \sigma' \tan \phi's=cтА▓+╧ГтА▓tan╧ХтА▓, where cтА▓c'cтА▓ and ╧ХтА▓\phi'╧ХтА▓ are effective stress parameters.

  • тЦ╕

    Option A is incorrect due to missing the normal stress variable.

  • тЦ╕

    Option B is incorrect as it transposes the shear strength (SSS) and cohesion (CCC) variables.

ЁЯУК Diagram / Illustration
Mohr-Coulomb Failure CriterionS = C + ╧Г tan ╧ЖWhere:S: Shear Strength | C: Cohesion | ╧Г: NormalStress | ╧Ж: Angle of Friction
тЬЕ

C is correct тАФ The Coulomb strength equation describes the shear strength SSS as S=C+╧ГtanтБб╧ХS = C + \sigma \tan \phiS=C+╧Гtan╧Х.

Core Concepts Used
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Shear Strength of Soil Mohr-Coulomb Criterion Effective Stress
ЁЯТб EXAM TIP

Always remember the difference between total stress parameters and effective stress parameters; in geotechnical problems, failure is usually governed by effective stress, ╧ГтА▓\sigma'╧ГтА▓.

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