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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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CivilSoil Mechanics
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Which of the following is coulomb’s strength equation?

A

S=C+tan⁡ϕS = C + \tan \phiS=C+tanϕ

B

C=S+σtan⁡ϕC = S + \sigma \tan \phiC=S+σtanϕ

C

S=C+σtan⁡ϕS = C + \sigma \tan \phiS=C+σtanϕ

D

S=tan⁡ϕS = \tan \phiS=tanϕ

Correct Answer

⚙️ TE • Technical Concept & PrincipleCivilSoil Mechanics
Option C

S=C+σtan⁡ϕS = C + \sigma \tan \phiS=C+σtanϕ

Quick Summary:

Coulomb's Law (or the Mohr-Coulomb failure criterion) states that the shear strength of a soil at failure is a linear function of the normal stress acting on the failure plane. It is expressed as the sum of cohesion (CCC) and the product of normal stress (σ\sigmaσ) and the tangent of the internal angle of friction (ϕ\phiϕ).

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

Coulomb's Law (or the Mohr-Coulomb failure criterion) states that the shear strength of a soil at failure is a linear function of the normal stress acting on the failure plane. It is expressed as the sum of cohesion (CCC) and the product of normal stress (σ\sigmaσ) and the tangent of the internal angle of friction (ϕ\phiϕ).

🔢 Key Formulas

S=C+σtan⁡ϕS = C + \sigma \tan \phiS=C+σtanϕ — The Mohr-Coulomb failure criterion equation

⚙️ Working Principle

The shear strength is composed of two components: the intrinsic cohesion (CCC) which represents the bonding between soil particles, and the frictional component (sigmatan⁡ϕsigma \tan \phisigmatanϕ) which arises from the intergranular contact and mechanical interlocking of soil particles under normal stress. As normal stress increases, the frictional resistance increases proportionally until failure occurs.

📌 Key Points
  • ▸

    Cohesion (CCC) is the shear strength at zero normal stress.

  • ▸

    The internal angle of friction (ϕ\phiϕ) represents the shear strength contributed by inter-particle friction.

  • ▸

    The equation assumes a linear relationship between shear strength and normal stress.

  • ▸

    This criterion is foundational for stability analysis of slopes and earth retaining structures.

✅ Advantages
  • ▸

    Simple mathematical model for complex soil behavior

  • ▸

    Easily derived from standard laboratory tests like Direct Shear or Triaxial tests

❌ Disadvantages / Limitations
  • ▸

    Assumes linear behavior which may not hold for all soil types at high pressures

  • ▸

    Does not account for pore water pressure unless effective stress is explicitly considered

🛠️ Applications / Uses
  • ▸

    Bearing capacity analysis of foundations

  • ▸

    Slope stability assessment

  • ▸

    Lateral earth pressure calculations in retaining walls

📄 Additional Information
  • ▸

    In terms of effective stress, the equation is expressed as s=c′+σ′tan⁡ϕ′s = c' + \sigma' \tan \phi's=c′+σ′tanϕ′, where c′c'c′ and ϕ′\phi'ϕ′ are effective stress parameters.

  • ▸

    Option A is incorrect due to missing the normal stress variable.

  • ▸

    Option B is incorrect as it transposes the shear strength (SSS) and cohesion (CCC) variables.

📊 Diagram / Illustration
Mohr-Coulomb Failure CriterionS = C + σ tan φWhere:S: Shear Strength | C: Cohesion | σ: Normal Stress | φ: Angle of Friction
✅

C is correct — The Coulomb strength equation describes the shear strength SSS as S=C+σtan⁡ϕS = C + \sigma \tan \phiS=C+σtanϕ.

Core Concepts Used
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Shear Strength of Soil Mohr-Coulomb Criterion Effective Stress
💡 EXAM TIP

Always remember the difference between total stress parameters and effective stress parameters; in geotechnical problems, failure is usually governed by effective stress, σ′\sigma'σ′.

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