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Chapter 1 of 12 • Page 1 of 248🔒 Protected PDF • Watermarked
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ElectricalElectromagnetics Field Theory
PrevNext

Which of the following is not a unit of inductance?

A

Henry

B

Coulomb/Volt-ampere

C

Volt-second/Ampere

D

All of above

Correct Answer

⚙️ TE • Technical Concept & PrincipleElectricalElectromagnetics Field Theory
Option B

Coulomb/Volt-ampere

Quick Summary:

Inductance (LLL) is defined by the relation v=Ldidtv = L \frac{di}{dt}v=Ldtdi​, which implies L=vdtdiL = v \frac{dt}{di}L=vdidt​. The SI unit of inductance is the Henry (H), which is equivalent to Volt-second per Ampere (V·s/A).

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

Inductance (LLL) is defined by the relation v=Ldidtv = L \frac{di}{dt}v=Ldtdi​, which implies L=vdtdiL = v \frac{dt}{di}L=vdidt​. The SI unit of inductance is the Henry (H), which is equivalent to Volt-second per Ampere (V·s/A).

🔢 Key Formulas

L=V⋅dtdiL = \frac{V \cdot dt}{di}L=diV⋅dt​ — Defining relation for inductance

1 H=1 V⋅s1 A1 \text{ H} = \frac{1 \text{ V} \cdot \text{s}}{1 \text{ A}}1 H=1 A1 V⋅s​ — Equivalence of Henry

⚙️ Working Principle

The inductance LLL relates the magnetic flux linkage Ψ\PsiΨ to current iii (L=Ψ/iL = \Psi/iL=Ψ/i) or the voltage drop across an inductor to the rate of change of current. Since Ψ\PsiΨ is measured in Weber (Wb) and 1 Wb=1 V⋅s1 \text{ Wb} = 1 \text{ V} \cdot \text{s}1 Wb=1 V⋅s, the unit becomes Volt⋅secondAmpere\frac{\text{Volt} \cdot \text{second}}{\text{Ampere}}AmpereVolt⋅second​, which is the Henry.

📌 Key Points
  • ▸

    Inductance measures the ability of a circuit to store energy in a magnetic field.

  • ▸

    The unit V⋅s/AV \cdot s / AV⋅s/A is derived directly from Faraday's Law of Induction.

  • ▸

    Option B (Coulomb/Volt-ampere) equates to C/(V⋅A)=(A⋅s)/(V⋅A)=s/VC / (V \cdot A) = (A \cdot s) / (V \cdot A) = s/VC/(V⋅A)=(A⋅s)/(V⋅A)=s/V, which represents Capacitance/Resistance or related terms, but not inductance.

🛠️ Applications / Uses
  • ▸

    Inductors in filter circuits

  • ▸

    Energy storage in magnetic components like transformers and motors

📄 Additional Information
  • ▸

    The dimension of inductance is [ML2T−2I−2][M L^2 T^{-2} I^{-2}][ML2T−2I−2].

  • ▸

    Option B simplifies to s/Vs/Vs/V (seconds per Volt), which is dimensionally inconsistent with inductance.

📊 Diagram / Illustration
Unit of Inductance (L)1 Henry = 1 Volt · second / AmpereDimension: [M L² T⁻² I⁻²]
✅

B is correct — Coulomb/Volt-ampere is not a valid representation of Henry, as it results in units of s/Vs/Vs/V rather than V⋅s/AV\cdot s/AV⋅s/A.

Core Concepts Used
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Inductance Electromagnetic Induction Dimensional Analysis
💡 EXAM TIP

Always verify dimensional consistency by breaking down units into fundamental SI units (kg, m, s, A) when dealing with electromagnetic variables.

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