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ElectricalMachine
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Which of the following is not an output equation of three-phase induction motor?

A

Q=C0D2LnsQ = C_{0} D^{2} L n_{s}Q=C0​D2Lns​

B

Q=(1.11π2KwBavac10−3)D2LnsQ = ( 1. 11 \pi ^{2} K_{w} B a_{v a c 10 -^{3 ) D 2} L n s}Q=(1.11π2Kw​Bavac10−3)D2Lns​

C

Q=3C0D2LnsQ = \sqrt{ 3 } C_{0} D^{2} L n_{s}Q=3​C0​D2Lns​

D

Q=(11KwBavac10−3)D2LnsQ = ( 11 K_{w} B a_{v a c 10 -^{3 ) D 2} L n s}Q=(11Kw​Bavac10−3)D2Lns​

Correct Answer

⚙️ TE • Technical Concept & PrincipleElectricalMachine
Option C

Q=3C0D2LnsQ = \sqrt{ 3 } C_{0} D^{2} L n_{s}Q=3​C0​D2Lns​

Quick Summary:

The output equation of a three-phase induction motor represents the relationship between the motor power output (Q) and its main dimensions, specifically the bore diameter (D) and core length (L). The standard output equation is derived as Q=C0D2LnsQ = C_0 D^2 L n_sQ=C0​D2Lns​, where C0C_0C0​ is the output coefficient involving specific magnetic and electric loadings.

⚙️TETechnical SolutionConcept & Principle
💡 Explanation

The output equation of a three-phase induction motor represents the relationship between the motor power output (Q) and its main dimensions, specifically the bore diameter (D) and core length (L). The standard output equation is derived as Q=C0D2LnsQ = C_0 D^2 L n_sQ=C0​D2Lns​, where C0C_0C0​ is the output coefficient involving specific magnetic and electric loadings.

🔢 Key Formulas

Q=C0D2LnsQ = C_0 D^2 L n_sQ=C0​D2Lns​ — Output equation of an induction motor

C0=1.11π2KwBavac10−3C_0 = 1.11 \pi^2 K_w B_{av} ac 10^{-3}C0​=1.11π2Kw​Bav​ac10−3 — Expression for the output coefficient

⚙️ Working Principle

The output coefficient C0C_0C0​ incorporates the specific magnetic loading (BavB_{av}Bav​), specific electric loading (acacac), and the winding factor (KwK_wKw​). The constant C0C_0C0​ is inherently defined such that it accounts for the three-phase nature of the system (the 3\sqrt{3}3​ factor is already absorbed into the definition of C0C_0C0​). Therefore, including an additional 3\sqrt{3}3​ as shown in option C results in an incorrect dimensioned equation.

📌 Key Points
  • ▸

    The output coefficient C0C_0C0​ is defined as 1.11π2KwBavac10−31.11 \pi^2 K_w B_{av} ac 10^{-3}1.11π2Kw​Bav​ac10−3.

  • ▸

    The product D2LD^2 LD2L is known as the output constant dimension.

  • ▸

    The 3\sqrt{3}3​ factor is integrated into the calculation of C0C_0C0​ for 3-phase machines, making option C redundant and incorrect.

✅ Advantages
  • ▸

    Provides a quick estimation of machine size for a given power rating.

  • ▸

    Useful in initial design stages of electrical machines.

❌ Disadvantages / Limitations
  • ▸

    It is a design approximation based on average flux and current densities.

  • ▸

    Does not account for temperature rise or efficiency losses directly.

🛠️ Applications / Uses
  • ▸

    Preliminary sizing of industrial AC motors.

  • ▸

    Comparison of machine designs based on volume utilization.

📄 Additional Information
  • ▸

    Option B is a standard form of the output equation where C0C_0C0​ is fully expanded.

  • ▸

    Option D is an alternative simplified form often used where numerical constants are condensed.

  • ▸

    The constant 1.111.111.11 comes from the form factor of the AC supply voltage.

📊 Diagram / Illustration
Output Equation ComponentsQ = C₀ D² L nₛC₀ = 1.11 π² K_w B_av ac 10⁻³Note: The √3 factor is already included within the constant C₀
✅

C is correct — The 3\sqrt{3}3​ factor is already embedded within the output coefficient C0C_0C0​ definition; multiplying it again is mathematically incorrect.

Core Concepts Used
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Specific Magnetic Loading ($B_{av}$) Specific Electric Loading ($ac$) Output Coefficient ($C_0$)
💡 EXAM TIP

Always verify if the 3\sqrt{3}3​ factor is inside your constant C0C_0C0​ or KKK when calculating power for 3-phase machines; don't count it twice!

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