Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
Which of the given options can replace the question mark (?) in the following series to make it logically complete? BDF 25 CEG 20 EGI 15 GIK 10 ?
IKM 5
HJL 5
IKM 0
HJL 0
IKM 5
Analyze the alphanumeric series by splitting it into two independent components: the letter triplets and the decrementing numbers.
Analyze the alphanumeric series by splitting it into two independent components: the letter triplets and the decrementing numbers.
Analyze the letter pattern
Each triplet follows the pattern: First letter (+2), Second letter (+2), Third letter (+2). Starting letters: B(2), C(3), E(5), G(7). The sequence of starting letters is B(+1) тЖТ C(+2) тЖТ E(+2) тЖТ G(+2). Following this, G(+2) gives I. The triplet starting with I is I(+2)=K, K(+2)=M. Thus, IKM.
Analyze the numeric pattern
The numbers follow a simple arithmetic progression: 25, 20, 15, 10. Each term decreases by 5. Therefore, the next number after 10 is 10 - 5 = 5.
Combine findings
Combining the letters IKM and the number 5, we get IKM 5.
B) HJL 5 is incorrect because the letter pattern shift requires IKM; C) IKM 0 is incorrect because the numeric sequence follows a -5 rule resulting in 5, not 0; D) HJL 0 is incorrect as it fails both the letter and the numeric pattern tests.
A is correct because the series follows a pattern where letters increment by 2 within triplets and start positions increase by 2 (after the first step), while the numbers decrease consistently by 5.
In alphanumeric series, always separate digits from alphabets immediately to prevent mental fatigue and simplify the logic for each component individually.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants