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16 address line can access total no. of _____ bytes.
64K
65535
Both
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None
Both
Normal 0
false false false
EN-US X-NONE GU
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A processor with N address lines can access 2°N unique memory locations. For N=16, the address space is 2°16=65,536 bytes, which is commonly referred to as 64KB (where 1K = 1024 bytes).
A processor with N address lines can access 2°N unique memory locations. For N=16, the address space is 2°16=65,536 bytes, which is commonly referred to as 64KB (where 1K = 1024 bytes).
TotalCapacity=2°Nbytes
2°16=65,536
The CPU uses binary addressing to identify memory cells. Each address line represents one bit of the address bus. With 16 lines, the range of possible addresses is 0000 to FFFF in hexadecimal notation, corresponding to 0 to 65,535 in decimal, resulting in a total capacity of 65,536 distinct addresses.
Address bus width determines the maximum directly addressable memory size.
The prefix 'K' in memory terminology represents 2°10=1024 units.
A 16-bit address bus is standard for 8-bit microprocessors like the 8085.
Simple mapping of address lines to physical memory.
Efficient utilization of address space in small-scale systems.
Limited memory capacity (only 64KB) compared to modern systems.
Requires paging or banking techniques to extend memory beyond 64KB.
8-bit embedded system design.
Microprocessor architecture training kits.
Small-scale ROM/RAM interface circuits.
In computer architecture, 1K=1024. Thus, 65536/1024=64K.
Option B (65535) is the highest address value, but the total number of bytes (capacity) is 65536.
C is correct — 16 address lines provide 2°16 memory locations, which equals 65,536 bytes or 64K.
Always verify if a question asks for the 'highest address' (which is 2°N−1) or the 'total number of addressable locations' (which is 2°N).