16 address line can access total no. of _____ bytes.

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Both

Explanation: A processor with $N$ address lines can access $2^N$ unique memory locations. For $N = 16$, the address space is $2^{16} = 65,536$ bytes, which is commonly referred to as 64KB (where 1K = 1024 bytes). Working Principle: The CPU uses binary addressing to identify memory cells. Each address line represents one bit of the address bus. With 16 lines, the range of possible addresses is $0000$ to $FFFF$ in hexadecimal notation, corresponding to $0$ to $65,535$ in decimal, resulting in a total capacity of $65,536$ distinct addresses. Key Formulas: $Total \, Capacity = 2^N \, bytes$; $2^{16} = 65,536$ Key Points: Address bus width determines the maximum directly addressable memory size.; The prefix 'K' in memory terminology represents $2^{10} = 1024$ units.; A 16-bit address bus is standard for 8-bit microprocessors like the 8085. Advantages: Simple mapping of address lines to physical memory.; Efficient utilization of address space in small-scale systems. Disadvantages: Limited memory capacity (only 64KB) compared to modern systems.; Requires paging or banking techniques to extend memory beyond 64KB. Applications: 8-bit embedded system design.; Microprocessor architecture training kits.; Small-scale ROM/RAM interface circuits. Additional Info: In computer architecture, $1K = 1024$. Thus, $65536 / 1024 = 64K$.. Option B (65535) is the highest address value, but the total number of bytes (capacity) is 65536. Answer: C is correct — 16 address lines provide $2^{16}$ memory locations, which equals 65,536 bytes or 64K. Exam Tip: Always verify if a question asks for the 'highest address' (which is $2^N - 1$) or the 'total number of addressable locations' (which is $2^N$).

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