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The interfacing of 256 bytes memory using _______address line.
2
4
8
16
8
The number of address lines required for a memory chip is determined by the relationship 2┬░n=N, where n is the number of address lines and N is the total number of memory locations in bytes. For a 256-byte memory, N=256, which is equivalent to 2┬░8.
The number of address lines required for a memory chip is determined by the relationship 2┬░n=N, where n is the number of address lines and N is the total number of memory locations in bytes. For a 256-byte memory, N=256, which is equivalent to 2┬░8.
N=2┬░n тАФ where N is memory capacity in bytes and n is the number of address lines.
n=log2тАЛ(N) тАФ formula to calculate required address lines.
The microprocessor identifies each unique memory location using a binary address. Each address line represents one bit of the address bus. By using 8 address lines, the system can generate 2┬░8=256 unique combinations, ranging from 000000002тАЛ to 111111112тАЛ, which perfectly addresses each of the 256 individual byte locations.
Memory capacity is always a power of 2 in standard digital architectures.
Each address line acts as a binary selector.
The total addressable memory space increases exponentially with each additional line.
Efficient utilization of address bus space.
Predictable memory mapping for firmware design.
Requires decoding logic if multiple memory chips are used.
Limited capacity per chip compared to higher-density memories.
Embedded system firmware storage.
Look-up table (LUT) implementations in microcontrollers.
For 1┬аKB=1024┬аbytes, n=10 lines are required.
Option A (2 lines) covers 4 bytes, Option B (4 lines) covers 16 bytes, and Option D (16 lines) covers 65,536 bytes (64 KB).
C is correct тАФ Since 2┬░8=256, a memory capacity of 256 bytes requires exactly 8 address lines to uniquely identify every byte.
Always remember the powers of 2 (2, 4, 8, 16, 32, 64, 128, 256, 512, 1024) to quickly solve addressing problems without calculation.