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20 ml of NaOH is neutralised by 10 ml of HNO 3 . How much NaOH will be required to neutralise 15 ml of HNO 3 ?
20 ml
40 ml
30 ml
25 ml
30 ml
In a neutralisation reaction, the amount of acid and base required is proportional to their concentrations. Since 20┬аml of NaOH neutralises 10┬аml of HNO3тАЛ, the ratio of NaOH to HNO3тАЛ is 2:1. To neutralise 15┬аml of HNO3тАЛ, we require 15├Ч2=30┬аml of NaOH.
In a neutralisation reaction, the amount of acid and base required is proportional to their concentrations. Since 20┬аml of NaOH neutralises 10┬аml of HNO3тАЛ, the ratio of NaOH to HNO3тАЛ is 2:1. To neutralise 15┬аml of HNO3тАЛ, we require 15├Ч2=30┬аml of NaOH.
Think of it like a recipe: if 2 cups of sugar (NaOH) are needed for every 1 cup of flour (HNO3тАЛ), then for 15 cups of flour, you must scale up the sugar by the same factor (15) to maintain the balance.
Equivalence: N1тАЛV1тАЛ=N2тАЛV2тАЛ
VNaOHтАЛ=2├ЧVHNO3тАЛтАЛ тАФ Relationship based on the given experimental data
N1тАЛV1тАЛ=N2тАЛV2тАЛ тАФ Law of equivalence in titration
The principle of neutralisation involves the reaction NaOH+HNO3тАЛтЖТNaNO3тАЛ+H2тАЛO. According to the Law of Equivalence, N1тАЛV1тАЛ=N2тАЛV2тАЛ. Given the volume ratio, we apply the unitary method to find the proportional volume of base required for the new volume of acid.
Neutralisation occurs when H+ ions from the acid react with OHтИТ ions from the base to form water.
The volume of titrant required is directly proportional to the amount of solute in the analyte.
This calculation uses the unitary method based on observed stoichiometric proportions.
Simple linear relationship
Easy to calculate using unitary method
Volumetric titration analysis
pH adjustment in industrial wastewater treatment
The ratio 20:10 simplifies to 2:1, implying that NaOH is twice as concentrated or required in double the volume compared to this specific HNO3тАЛ concentration.
Option B (40 ml) would be correct if HNO3тАЛ volume were 20 ml.
C is correct тАФ Since 20 ml of NaOH is needed for 10 ml of HNO3, the ratio is 2:1; therefore, 15 ml of HNO3 requires 30 ml of NaOH.
Always verify if the concentration of the acid/base changes; if not, you can simply use the ratio of volumes directly as demonstrated here.
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