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40 ml of HCl is neutralized by 20 ml of KOH. How much HCl will be required to neutralize 35 ml of KOH?
60 ml
70 ml
80 ml
50 ml
70 ml
Neutralization reactions follow the stoichiometry of the acid-base reaction, where equivalent amounts of acid and base react completely. Since 40┬аml of HCl neutralizes 20┬аml of KOH, the volume ratio of HCl to KOH is 2:1. Thus, 35┬аml of KOH will require twice that volume, which is 70┬аml of HCl.
Neutralization reactions follow the stoichiometry of the acid-base reaction, where equivalent amounts of acid and base react completely. Since 40┬аml of HCl neutralizes 20┬аml of KOH, the volume ratio of HCl to KOH is 2:1. Thus, 35┬аml of KOH will require twice that volume, which is 70┬аml of HCl.
Think of a recipe where you always need 2 cups of flour for every 1 cup of sugar; if you use 35 cups of sugar, you will need 70 cups of flour.
V1тАЛN1тАЛ=V2тАЛN2тАЛ тАФ Neutralization law for acid-base titration
VKOHтАЛVHClтАЛтАЛ=NHClтАЛNKOHтАЛтАЛ тАФ Volume-concentration proportionality
Using the relationship between volume and concentration, since both HCl and KOH are strong monoprotic acid and base respectively, the ratio of their reacting volumes is inversely proportional to their concentrations. The volume ratio is VKOHтАЛVHClтАЛтАЛ=2040тАЛ=2. Multiplying the given KOH volume (35┬аml) by this factor yields 70┬аml.
Neutralization occurs when moles of H+ ions equal moles of OHтИТ ions.
HCl is a strong monobasic acid and KOH is a strong monoacidic base.
The volume ratio remains constant for solutions of identical normality.
Acid-base titrations in analytical chemistry
Determining unknown concentrations in neutralization reactions
Both HCl and KOH react in a 1:1 molar ratio.
Option B is correct because 35├Ч2=70┬аml.
B is correct тАФ 70┬аml of HCl is required to neutralize 35┬аml of KOH based on the 2:1 volume ratio.
Always check the basicity of the acid and acidity of the base before applying the dilution or neutralization formula directly.
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