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A 415 V synchronous motor is working at 30° load angle. What can be the expected phasor?

Correct Answer

⚙️ TE • Technical Direct FormulaElectricalMachine

Option A

Quick Summary:

Given: Voltage V = 415 V, Load angle = 30°

📐MAMath SolutionDirect Formula

📋 Given

Voltage V = 415 V, Load angle = 30°

🔢 Formula Used

Vph=V∠δV_{ph} = V \angle \deltaVph​=V∠δ

📊 Diagram / Illustration

🔢 Step-by-Step Solution

Identify V and angle

The given voltage is $415 V$ and the load angle is $30°$ .

V=415V,δ=30°V = 415 V, \delta = 30°V=415V,δ=30°

Construct the phasor

Using the formula for phasor representation: $V_{ph} = V \angle \delta$ , we represent the voltage in phasor form.

Vph=415∠30°V_{ph} = 415 \angle 30°Vph​=415∠30°

Determine the expected phasor

The expected phasor is clearly shown to represent this angle and magnitude in the provided diagram.

Phasor corresponds to option A.

✅

A is correct because the phasor for $415 V$ at a $30°$ angle is correctly represented in option A.

Core Concepts Used

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💡 EXAM TIP

Understanding phasors is critical in both electrical engineering and control systems, linking it with complex numbers and AC analysis.

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