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The voltage equation of the synchronous motor is?
V=Eb+IaRa+jXs
V=Eb−IaRa+jXs
V=Eb+IaRa−jXs
V=Eb−IaRa−jXs
V=Eb+IaRa+jXs
The correct voltage equation for a synchronous motor is given by V=Eb+Ia(Ra+jXs), where V is the terminal voltage, Eb is the back electromotive force (EMF), Ia is the armature current, Ra is the armature resistance, and Xs is the synchronous reactance.
The correct voltage equation for a synchronous motor is given by V=Eb+Ia(Ra+jXs), where V is the terminal voltage, Eb is the back electromotive force (EMF), Ia is the armature current, Ra is the armature resistance, and Xs is the synchronous reactance.
V=Eb+Ia(Ra+jXs) — Terminal voltage equation of the synchronous motor
This equation describes the relationship between voltage, current, and the impedance faced by the current in the armature winding of the synchronous motor. The synchronous reactance represents the total opposition to current flow due to both resistance and inductive reactance at synchronous speed.
The synchronous motor operates at constant speed irrespective of load conditions.
The concept of synchronous reactance is crucial in determining the motor's performance characteristics.
High efficiency
Good power factor characteristics
Requires additional starting mechanisms
Sensitive to load changes
Used in power plants for synchronous generation
Drives in industrial applications requiring constant speed
Standard value or specification for synchronous reactance varies based on motor design and application.
Option B is incorrect because it uses a minus sign instead of a plus sign in the equation.
A is correct — it accurately represents the terminal voltage relationship in a synchronous motor.
Understanding the impedance in AC circuits is crucial when analyzing synchronous motors and their performance.