Join 60,000+ competitive exam aspirants
A, B, C, D, E, F and G are sitting around a circular table facing the centre. B sits third to the right of F. D sits fourth to the left of B. C is neither the immediate neighbour of B nor
None
One
Two
A sits third to the right of C. E is not the immediate neighbour of D. How many people sit between E and G, when counted from the left of E? Three
A sits third to the right of C. E is not the immediate neighbour of D. How many people sit between E and G, when counted from the left of E? Three
Place the fixed reference point (F) first, then place B, D, and C relative to the fixed circular positions to easily identify remaining spots for E, A, and G.
Place the fixed reference point (F) first, then place B, D, and C relative to the fixed circular positions to easily identify remaining spots for E, A, and G.
Establish Reference
Place F at position 1. Since B sits third to the right of F, B is at position 4. (Clockwise: F=1, pos 2, pos 3, B=4).
Placement of D, C, and A
D is fourth to the left of B. Moving counter-clockwise from B(4): 3, 2, 1, 7. So, D is at position 7. C is not a neighbor of B, and given C is not a neighbor of D, C sits at position 2. A must be at position 6 (third to the right of C).
Final Seating and Counting
The remaining spots for E and G are 5 and 3. E is not neighbor of D, so E is at position 5, leaving G at position 3. Counting from E(5) to the left (clockwise), we pass 4, 3, 2, 1... The distance includes G, F, A (Three people).
A: Incorrect, as the calculation confirms a specific count. B: Incorrect, only one result exists based on the constraints. C: Incorrect, the count is three, not two.
D is correct because based on the constraints (B 3rd right of F, D 4th left of B, C not neighbor of B/D), the only arrangement yields three people between E and G.
In circular puzzles, always fix the most stable entity (usually the person with multiple relative clues) to anchor your diagram, then fill the gaps.