Join 60,000+ competitive exam aspirants
Each of members , P, Q, R, S, T, U and V, of a certain department has to attend a seminar on different days of the same week starting from Monday to Sunday. T has to attend the seminar immediately before P. Q has to attend the seminar on Tuesday. V has to attend the seminar on Sunday. Only U has to attend the seminar between P and R. S has to attend the seminar on one of the days before Q. Who has to attend the seminar on Monday?
S
T
R
P
S
Map fixed positions first (Tuesday=Q, Sunday=V) then use the 'T immediately before P' and 'U between P and R' blocks to slot the remaining days.
Map fixed positions first (Tuesday=Q, Sunday=V) then use the 'T immediately before P' and 'U between P and R' blocks to slot the remaining days.
Establish Fixed Positions
Days are Mon, Tue, Wed, Thu, Fri, Sat, Sun. We know Tuesday is Q and Sunday is V. S must be before Q, so S must be Monday.
Verify S=Monday Constraint
If S is Monday and Q is Tuesday, we have 5 days left (Wed-Sat) for P, R, T, U. The block 'T immediately before P' and 'U between P and R' implies a sequence like T-P-U-R or R-U-P-T. Since Sunday is V, the only logical fit is Monday: S, Tuesday: Q, Wednesday: T, Thursday: P, Friday: U, Saturday: R, Sunday: V.
B: T attends on Wednesday, not Monday. C: R attends on Saturday, not Monday. D: P attends on Thursday, not Monday.
A is correct because S is the only person who can occupy Monday given the constraint that S must attend before Q (Tuesday) and all other slots are filled by the defined sequences.
In scheduling puzzles, always identify 'anchor' days first (like fixed days) to drastically reduce the number of possible permutations.