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Refer to the following word series and answer the question that follows. CAB BIT YET AFT In each of the words, each vowel is changed to the second letter following it in the English alphabetical order and each consonant is changed to the letter immediately preceding it in the English alphabetical order. In how many letter-clusters thus formed will NO vowel appear?
Four
Three
Two
One
One
Identify vowels in words (A, E, I, O, U). Since only vowels shift +2, they will likely remain vowels (A+2=C, E+2=G, I+2=K, O+2=Q, U+2=W), making it impossible to eliminate them unless the rule changes the vowel into a non-vowel.
Identify vowels in words (A, E, I, O, U). Since only vowels shift +2, they will likely remain vowels (A+2=C, E+2=G, I+2=K, O+2=Q, U+2=W), making it impossible to eliminate them unless the rule changes the vowel into a non-vowel.
Analyze transformation rules
Rule 1: Vowels (A, E, I, O, U) become the second letter following them (+2). Rule 2: Consonants become the letter preceding them (-1).
Apply rules to each word
CAB: C(cons -1)=B, A(vowel +2)=C, B(cons -1)=A. Result: BCA. BIT: B(cons -1)=A, I(vowel +2)=K, T(cons -1)=S. Result: AKS. YET: Y(cons -1)=X, E(vowel +2)=G, T(cons -1)=S. Result: XGS. AFT: A(vowel +2)=C, F(cons -1)=E, T(cons -1)=S. Result: CES.
Check for vowels in resulting clusters
BCA has A. AKS has A. XGS has none. CES has E. Only the cluster XGS has no vowel.
A: Four is incorrect as only one cluster qualifies. B: Three is incorrect as only one cluster qualifies. C: Two is incorrect as only one cluster qualifies.
D is correct because after transformation, only the word XGS (derived from YET) contains no vowels.
When asked for 'no vowels', focus primarily on tracking the vowels through the transformation. Often, vowels shifting by +2 will remain vowels, keeping the 'vowel-free' count low.
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