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Uday starts from Point Y and drives 16 km towards the North. He then takes a right turn, drives 28 km, turns right and drives 31 km. He then takes a right turn and drives 13 km. He takes a right turn and drives 41 km. He then turns left, drives 15 km, turns right and drives 8 km to stop at Point Z. How far (shortest distance) and towards which direction should he drive in order to reach Point Y again? (All turns are 90 degrees turns only unless specified)
34 km towards South
47 km towards North
49 km towards East
25 km towards South
34 km towards South
Track net displacement on X (East-West) and Y (North-South) axes separately. North/East are positive (+), South/West are negative (-).
Track net displacement on X (East-West) and Y (North-South) axes separately. North/East are positive (+), South/West are negative (-).
Calculate X and Y displacements
Starting at Y(0,0): 1. 16km N: (0, 16). 2. Right (East) 28km: (28, 16). 3. Right (South) 31km: (28, 16-31) = (28, -15). 4. Right (West) 13km: (28-13, -15) = (15, -15). 5. Right (North) 41km: (15, -15+41) = (15, 26). 6. Left (West) 15km: (15-15, 26) = (0, 26). 7. Right (North) 8km: (0, 26+8) = (0, 34).
Final Position Calculation
Point Z is at (0, 34) relative to Y(0,0). To return to Y(0,0) from (0, 34), Uday must move 34 km in the negative Y direction (South).
B: 47 km North is wrong because he is currently North of Y, not South. C: 49 km East is wrong as there is no horizontal displacement remaining. D: 25 km South is wrong because the remaining vertical distance is 34 km, not 25 km.
A is correct because the net displacement relative to the starting point Y is 34 km North, meaning he must travel 34 km South to return to his origin.
When multiple turns are given, maintain a small table of North-South and East-West values to avoid counting errors; don't rely on mental visualization for complex paths.