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A conductor has a current of 150 mA flowing through it with a resistance of 0.8 ╬й. Find the potential difference across the conductor.
5.3 V
120 V
18.75 V
0.12 V
0.12 V
The potential difference (voltage) across a conductor is calculated using Ohm's Law as the product of current and resistance. Substituting the given values (I=150┬аmA=0.15┬аA and R=0.8┬а╬й) yields V=0.15┬аA├Ч0.8┬а╬й=0.12┬аV.
The potential difference (voltage) across a conductor is calculated using Ohm's Law as the product of current and resistance. Substituting the given values (I=150┬аmA=0.15┬аA and R=0.8┬а╬й) yields V=0.15┬аA├Ч0.8┬а╬й=0.12┬аV.
Think of electrical resistance like a narrow pipe and current as the flow of water. The potential difference is the water pressure needed to push a specific amount of water through that narrow pipe.
VIR: Voltage equals Current times Resistance (V=I├ЧR).
V=I├ЧR тАФ Ohm's Law relating Voltage (V), Current (I), and Resistance (R)
IAтАЛ=1000ImAтАЛтАЛ тАФ Conversion formula from milliamperes to amperes
Ohm's Law states that the current (I) flowing through a metallic conductor is directly proportional to the potential difference (V) applied across its ends, provided physical conditions like temperature remain constant. Mathematically, V=I├ЧR. Since current is given in milliamperes (mA), it must first be converted to amperes (A) by dividing by 1000 before applying the formula.
Always convert milliamperes (mA) to amperes (A) before performing standard SI calculations.
Ohm's Law is foundational for analyzing simple DC electrical circuits.
Potential difference is measured in Volts (V), current in Amperes (A), and resistance in Ohms (╬й).
Simple and direct application of Ohm's Law.
Essential for basic electrical circuit analysis in competitive examinations.
Assumes constant temperature and resistance, which may vary in real physical conditions due to heating effects.
Calculating voltage drops across resistors in electronic circuits.
Designing lighting and motor circuits in electrical engineering.
1 mA = 10тИТ3 A. Therefore, 150\text{ mA} = 150 \times 10тБ╗3\text{ A} = 0.15\text{ A}.$
Wrong options (A, B, C) typically arise from failing to convert milliamperes to amperes or through incorrect decimal placement.
D is correct тАФ The potential difference is 0.12 V calculated by multiplying 0.15 A by 0.8╬й.
Watch out for unit prefixes like mA (milli) or k╬й (kilo) in numerical problems. Always convert values to standard SI units (Amperes, Volts, Ohms) before plugging them into formulas to avoid common calculation traps.
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