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A cylindrical rod has an outer curved surface area of 4500┬аcm2. If the length of the rod is 39┬аcm, then the outer radius (in cm) of the rod, correct to two places of decimal, is: (Take ╧А=722тАЛ)
18.37
17.85
19.26
16.54
18.37
Use the formula r=2╧АhCSAтАЛ. Given CSA=4500, h=39, and ╧А=22/7, calculation simplifies to r=2├Ч22├Ч394500├Ч7тАЛтЙИ171631500тАЛтЙИ18.356.
Outer curved surface area of the cylindrical rod = 4500 cm┬▓, Length (height) of the rod = 39 cm, value of ╧А = 22/7.
CSA=2├Ч╧А├Чr├Чh
Use the formula r=2╧АhCSAтАЛ. Given CSA=4500, h=39, and ╧А=22/7, calculation simplifies to r=2├Ч22├Ч394500├Ч7тАЛтЙИ171631500тАЛтЙИ18.356.
Confusing the curved surface area (CSA) with the total surface area (TSA) or failing to divide by 2╧Аh correctly in the decimal calculation.
State the formula
The curved surface area (CSA) of a cylinder is given by CSA=2╧Аrh, where r is the radius and h is the height.
CSA=2├Ч╧А├Чr├Чh
Substitute given values
Substitute CSA=4500, h=39, and ╧А=22/7 into the formula: 4500=2├Ч(22/7)├Чr├Ч39.
4500=2├Ч722тАЛ├Чr├Ч39
Solve for r
Isolate r: r=2├Ч22├Ч394500├Ч7тАЛ=171631500тАЛ.
r=171631500тАЛтЙИ18.3566
Round to two decimal places
Rounding 18.3566 to two decimal places gives 18.36.
rтЙИ18.36
A is correct because the calculated outer radius is approximately 18.36 cm.
This concept of cylindrical surface area is frequently used in engineering problems involving pipeline volume or heat dissipation in mechanical components.