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A hollow cylindrical pipe has an external radius of 7 cm, internal radius of 6 cm, and height of 20 cm. Find the total surface area of the pipe (both ends included). (Use π=722)
1600 cm²
1716 cm²
1485 cm²
1670 cm²
1716 cm²
Calculate the surface area as: 2×722×[R×h+r×h+(R2−r2)]. Since R2−r2=(7+6)(7−6)=13, substitute values: 2×722×[7(20)+6(20)+13]=2×722×273=44×39=1716.
External radius R = 7 cm, internal radius r = 6 cm, height h = 20 cm, and pi = 22/7.
TSA=2π(R+r)(h+R−r)+2π(R2−r2)
Calculate the surface area as: 2×722×[R×h+r×h+(R2−r2)]. Since R2−r2=(7+6)(7−6)=13, substitute values: 2×722×[7(20)+6(20)+13]=2×722×273=44×39=1716.
Students often calculate the Lateral Surface Area (2πRh+2πrh) and forget to add the area of the two circular rings at the top and bottom (2×π(R2−r2)).
Calculate lateral surface areas
Calculate the sum of the external and internal curved surface areas using the formula 2πRh+2πrh.
2×722×(7×20+6×20)=2×722×260=711440
Calculate area of the two rings
Calculate the area of the two circular ring-shaped ends using 2×π(R2−r2).
2×722×(72−62)=2×722×(49−36)=2×722×13=7572
Calculate total surface area
Add the lateral surface area and the area of the ends: 711440+7572=712012.
712012=1716
B is correct because the total surface area calculation results in exactly 1716 cm².
This formula is a specific application of the general surface area of a composite solid; remember to always check if the ends are 'open' or 'closed' in such problems.