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A man covers 1/3 of his journey at 20 km/h, 1/3 at 30 km/h, and the remaining at 60 km/h. Find the average speed.
30 ┬аkm/h
35 ┬аkm/h
40 ┬аkm/h
25 ┬аkm/h
30 ┬аkm/h
For equal distances, use the harmonic mean formula or assume a total distance equal to the LCM of the speeds.
Journey divided into three equal parts with speeds 20 km/h, 30 km/h, and 60 km/h respectively.
Average┬аSpeed=v1тАЛ1тАЛ+v2тАЛ1тАЛ+v3тАЛ1тАЛ3тАЛ
For equal distances, use the harmonic mean formula or assume a total distance equal to the LCM of the speeds.
Students frequently calculate the simple arithmetic mean of the speeds instead of using total distance divided by total time.
Assume journey segments
Let the total distance be 3d, meaning each one-third portion covers a distance of d.
Distance┬аper┬аsegment=d
Calculate time for each segment
Compute the time taken for each of the three parts using the formula time equals distance over speed.
t1тАЛ=20dтАЛ,t2тАЛ=30dтАЛ,t3тАЛ=60dтАЛ
Find total time
Add the individual times to find the total time taken for the journey.
T=20dтАЛ+30dтАЛ+60dтАЛ=606dтАЛ=10dтАЛ
Calculate average speed
Divide the total distance by the total time to arrive at the final average speed.
Average┬аSpeed=10dтАЛ3dтАЛ=30┬аkm/h
A is correct because the calculated average speed is 30 km/h.
Similar weighted-average principles apply in mixtures and allegations as well as combined rate problems.