A man sold an article for ₹346 by first giving a d% discount o... | Mathematics MCQ | Examoogle

MathematicsPrevious Year Paper 2024

A man sold an article for ₹346 by first giving a d% discount on its marked price, and then another discount having the same nominal value (in ₹). If the marked price of the article is ₹1730, then what is the value of d?

$44$

$43$

$40$

$38$

Correct Answer

📐 MA • Math Algebraic EquationMathematicsPrevious Year Paper 2024

Option C

$40$

Quick Summary:

Test Option C ( $d = 40$ ): First discount $= 40\%$ of $1730 = ₹692$ . Second discount also $= ₹692$ . Total discount $= 692 + 692 = ₹1384$ . Selling Price $= 1730 - 1384 = ₹346$ . This instantly matches the given selling price!

🎯

Crack Previous Year Paper 2024 with Examoogle SuperTeachers

Get Free Demo Classes & Live Mocks →

📐MAMath SolutionAlgebraic Equation

📋 Given

Marked Price (MP) = ₹1730, Selling Price (SP) = ₹346, Discount 1 = d%, Discount 2 = ₹N where N is the nominal rupee value of Discount 1.

🔢 Formula Used

SP=MP−Discount1−Discount2\text{SP} = \text{MP} - \text{Discount}_1 - \text{Discount}_2SP=MP−Discount1​−Discount2​

⚡ Exam Hall Shortcut / Speed Trick

⚠️ Common Student Trap / Pitfall

Confusing 'another discount having the same nominal value (in ₹)' with a second discount of $d\%$ on the reduced price, or failing to realize both discounts have equal rupee value $17.3d$ .

📊 Diagram / Illustration

🔢 Step-by-Step Solution

Express the nominal value of the first discount

The marked price is $\text{MP} = ₹1730$ . A discount of $d\%$ is given, so the value of this discount in rupees is:

Discount1=d100×1730=17.3d\text{Discount}_1 = \frac{d}{100} \times 1730 = 17.3dDiscount1​=100d​×1730=17.3d

Incorporate the second discount

The question states that the second discount has the same nominal value (in ₹) as the first discount. Thus, both discounts are equal in rupee value:

Discount2=Discount1=17.3d\text{Discount}_2 = \text{Discount}_1 = 17.3dDiscount2​=Discount1​=17.3d

Set up the equation for Total Discount and Selling Price

The total discount subtracted from the Marked Price yields the Selling Price (₹346):

SP=MP−(Discount1+Discount2)\text{SP} = \text{MP} - (\text{Discount}_1 + \text{Discount}_2)SP=MP−(Discount1​+Discount2​)

Solve for d

Substitute the values into the equation and solve for $d$ :

346=1730−(17.3d+17.3d)346 = 1730 - (17.3d + 17.3d)346=1730−(17.3d+17.3d)

Simplify and calculate

Rearrange terms to isolate $d$ :

34.6d=1730−346=1384  ⟹  d=138434.6=4034.6d = 1730 - 346 = 1384 \implies d = \frac{1384}{34.6} = 4034.6d=1730−346=1384⟹d=34.61384​=40

✅

C is correct because setting $d = 40$ gives a total discount of $2 \times (40\% \text{ of } 1730) = 2 \times 692 = ₹1384$ , resulting in a final selling price of $1730 - 1384 = ₹346$ .

Core Concepts Used

Click any tag to open in AI Tutor

Marked Price & Selling Price Percentage Discounts Nominal Value vs Percentage Discount

💡 EXAM TIP

Always read discount problems carefully to distinguish between successive percentage discounts (where the second discount is applied to the reduced price) and equal nominal discounts (where the rupee amounts are identical).

Was this solution helpful?

⚡ Practice on Android App · 4.8 ★

Solve 10,000+ More Questions with AI Tutor

Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.

Free Download • 100K+ Aspirants

Discussion (0)

Loading discussion...

Prev Next

Correct Answer

Solve 10,000+ More Questions with AI Tutor

Related Questions

Discussion (0)