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A motorcycle increases its speed from 10 m/s to 30 m/s in 4 seconds. Find the acceleration of the motorcycle.
5 m/s┬▓
10 m/s┬▓
2.5 m/s┬▓
8 m/s┬▓
5 m/s┬▓
Acceleration is defined as the rate of change of velocity per unit time. By calculating the difference between the final velocity (30┬аm/s) and initial velocity (10┬аm/s) and dividing it by the time interval (4┬аs), we get the acceleration value of 5┬аm/s2.
Acceleration is defined as the rate of change of velocity per unit time. By calculating the difference between the final velocity (30┬аm/s) and initial velocity (10┬аm/s) and dividing it by the time interval (4┬аs), we get the acceleration value of 5┬аm/s2.
Think of it as stepping on the accelerator of a car; the 'kick' you feel in your seat is proportional to how quickly your speed increases, which is your acceleration.
Remember 'V-U over T' (Velocity final minus Initial, over Time).
a=tvтИТuтАЛ тАФ formula for acceleration where a is acceleration, v is final velocity, u is initial velocity, and t is time.
Acceleration is governed by Newton's laws of motion. It represents the vector change in velocity. The formula a=tvтИТuтАЛ calculates the uniform acceleration when the change in velocity is constant over a given time duration.
Acceleration is a vector quantity, meaning it has both magnitude and direction.
The SI unit for acceleration is m/s2.
If acceleration is constant, the velocity-time graph will be a straight line.
Uniform acceleration allows for predictable motion calculations.
Real-world motorcycle acceleration is rarely perfectly constant.
Design of automotive engines for performance metrics.
Analysis of traffic flow and road safety dynamics.
Initial velocity (u) = 10┬аm/s, Final velocity (v) = 30┬аm/s, Time (t) = 4┬аs. Calculation: a=430тИТ10тАЛ=420тАЛ=5┬аm/s2.
Option B (10┬аm/s2) is incorrect because the numerator 20 divided by 4 is 5, not 10.
A is correct тАФ The acceleration of the motorcycle is calculated as 5┬аm/s2.
Always ensure your units are consistent (m, s, m/s) before applying kinematic equations to avoid calculation errors.
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