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A train travels 300 km at a speed of 60 km/h and returns the same distance at 40 km/h. What is the average speed for the entire journey?
48┬аkm/h
50┬аkm/h
52┬аkm/h
45┬аkm/h
48┬аkm/h
When the distance traveled is the same in both directions, the average speed is simply the harmonic mean of the two speeds, independent of the actual distance value.
Distance d = 300 km, Speed s1 = 60 km/h, Speed s2 = 40 km/h
AverageSpeed=s1тАЛ+s2тАЛ2├Чs1тАЛ├Чs2тАЛтАЛ
When the distance traveled is the same in both directions, the average speed is simply the harmonic mean of the two speeds, independent of the actual distance value.
A common mistake is taking the arithmetic mean of the two speeds (i.e., (60 + 40) / 2 = 50 km/h) instead of using the harmonic mean formula.
Identify the Given Values
We are given the forward speed s1тАЛ=60┬аkm/h and the return speed s2тАЛ=40┬аkm/h for an equal distance of 300┬аkm each way.
s1тАЛ=60,s2тАЛ=40
Apply the Average Speed Formula
For equal distances covered at two different speeds, the average speed is given by the formula for the harmonic mean of speeds.
AverageSpeed=s1тАЛ+s2тАЛ2├Чs1тАЛ├Чs2тАЛтАЛ
Substitute the Values
Substitute s1тАЛ=60 and s2тАЛ=40 into the formula to compute the numerator and denominator.
AverageSpeed=60+402├Ч60├Ч40тАЛ=1004800тАЛ
Calculate the Final Result
Dividing 4800 by 100 gives the final average speed of the entire journey.
AverageSpeed=48┬аkm/h
A is correct because the calculated average speed is 48 km/h.
This harmonic mean concept is also frequently applied in problems involving work and time, where two entities work at different rates over the same amount of work.