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A tree standing on level ground is broken by a storm. The broken part bends and touches the ground, making an angle of 30° with the ground. The distance between the foot of the tree and the point where the top of the tree touches the ground is 12 m. Find the original height of the tree.
182
183
122
123
123
Use the 30°-60°-90° triangle ratio: base:perpendicular:hypotenuse = 3:1:2. Here, 3units = 12 m. Total height = 1 + 2 = 3 units. So, 3×312=123 m.
Angle of elevation = 30°, horizontal distance from base to broken top = 12 m.
tan(θ)=BasePerpendicular,cos(θ)=HypotenuseBase
Use the 30°-60°-90° triangle ratio: base:perpendicular:hypotenuse = 3:1:2. Here, 3units = 12 m. Total height = 1 + 2 = 3 units. So, 3×312=123 m.
Many students calculate only the broken part (hypotenuse = 83m)or only the standing part (height = 43m)instead of summing them together.
Define the triangle components
Let h1 be the standing part (perpendicular) and h2 be the broken part (hypotenuse). The base is given as 12 m.
Base=12,θ=30°
Calculate the standing part
Using tan(30°), we find the height of the standing part h1=12×tan(30°).
h1=12×31=312=43
Calculate the broken part
Using cos(30°), we find the length of the broken part h2=cos(30°)12.
h2=3/212=324=83
Calculate total height
The original height of the tree is the sum of the standing part and the broken part.
Total Height=h1+h2=43+83=123
D is correct because the total height is the sum of the perpendicular and hypotenuse of the triangle, which equals 123 m.
This concept of broken structures is frequently used in geometry problems involving ladders or poles. Always visualize the broken segment as the hypotenuse of a right-angled triangle.