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Among five people named A, B, C, D and E, each has a certain age. C is twice the age of
A is three times the age of D. D is one fifth the age of B. The age of B is 45. If E is equal the age of C, what is the age of E? 52
58
54
56
54
Work backwards from the known value (B=45) to find D, then use D to find A, and finally calculate C (which equals E) using the relationship given.
Work backwards from the known value (B=45) to find D, then use D to find A, and finally calculate C (which equals E) using the relationship given.
Calculate Age of D
Given B = 45. D is one-fifth of B, so D = 45 / 5 = 9.
Calculate Age of A
A is three times the age of D, so A = 3 * 9 = 27.
Calculate Age of C and E
C is twice the age of A, so C = 2 * 27 = 54. Since E = C, E = 54.
A: 52 is incorrect because the calculation leads to 54. B: 58 is incorrect as it does not satisfy the derived relations. D: 56 is incorrect because 27 multiplied by 2 equals 54, not 56.
C is correct because the sequential application of the given ratios (D=9, A=27, C=54) confirms that E equals 54.
In age-related problems, always define all variables in terms of one constant or build a chain of dependency to avoid calculation errors.
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