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Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group? (Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster.) 4778
DZA
CYZ
MJK
EAB
MJK
Calculate the alphabetical jump between letters in each cluster; three clusters will follow a consistent pattern (e.g., +x, +y), while the odd one will not.
Calculate the alphabetical jump between letters in each cluster; three clusters will follow a consistent pattern (e.g., +x, +y), while the odd one will not.
Analyze Cluster DZA
D (4) to Z (26) is -4 (or +22). Z (26) to A (1) is +1. The cycle of alphabet allows Z+1 to result in A.
Analyze Cluster CYZ
C (3) to Y (25) is -4. Y (25) to Z (26) is +1.
Analyze Cluster EAB
E (5) to A (1) is -4. A (1) to B (2) is +1.
Analyze Cluster MJK
M (13) to J (10) is -3. J (10) to K (11) is +1. This pattern deviates from the -4, +1 rule found in the other clusters.
A: DZA follows the rule (-4, +1), B: CYZ follows the rule (-4, +1), D: EAB follows the rule (-4, +1).
C is correct because MJK is the only cluster that does not follow the -4, +1 alphabetical jump pattern shared by the other three options.
When dealing with letter clusters, always convert letters to their numerical positions (A=1, B=2, ..., Z=26) to quickly identify constant differences or cycles.
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