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Based on the alphabetical order, three of the following four are alike in a certain way and thus form a group. Which is the one that does not belong to that group? (Note: The odd man out is not based on the number of consonants/vowels or their position in the letter cluster.) 6135
DEK
GHN
NOU
NOD
NOD
Observe the numerical positions of the letters in the alphabet and check the difference between consecutive letters (e.g., pos2 - pos1 and pos3 - pos2).
Observe the numerical positions of the letters in the alphabet and check the difference between consecutive letters (e.g., pos2 - pos1 and pos3 - pos2).
Analyze Letter Positions
Convert letters to their numerical positions (A=1, B=2, ..., Z=26): A) D(4), E(5), K(11); B) G(7), H(8), N(14); C) N(14), O(15), U(21); D) N(14), O(15), D(4).
Evaluate Differences
Calculate the differences (pos2-pos1, pos3-pos2): A: 5-4=+1, 11-5=+6. B: 8-7=+1, 14-8=+6. C: 15-14=+1, 21-15=+6. D: 15-14=+1, 4-15=-11.
Identify Odd One Out
Options A, B, and C follow the pattern of (+1, +6). Option D does not follow this pattern.
A, B, and C follow the consistent alphabetical gap pattern of +1 and +6 between consecutive letters; D fails this pattern.
D is correct because it is the only letter cluster that does not follow the (+1, +6) positional difference pattern found in the other three options.
When comparing three-letter clusters, always calculate the numerical gaps between characters first as it is the most common pattern in SSC-level reasoning.
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