Calculate height of the first triangle

Using the area formula $A = \frac{1}{2} \times b \times h$, solve for $h_1$ with $A_1 = 98$ and $b = 14$.

$98 = \frac{1}{2} \times 14 \times h_1 \implies h_1 = \frac{98 \times 2}{14} = 14 \text{ cm}$

Calculate area of the second triangle

The second triangle's area $A_2$ is twice that of the first.

$A_2 = 2 \times 98 = 196 \text{ cm}^2$

Find height of the second triangle

Use the same base $b = 14$ and new area $A_2 = 196$ to find $h_2$.

$196 = \frac{1}{2} \times 14 \times h_2 \implies h_2 = \frac{196 \times 2}{14} = 28 \text{ cm}$