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Each of M, N, O, P, Q, R and S plays a game on a different day of a week starting from Monday and ending on Sunday of the same week. M plays the game on Wednesday. Only two persons play the games between M and Q. O plays the game on the day immediately before R but not on Thursday. Only two persons play the games between N and S. N does not play the game on the last day. On which day does P play the game?
Monday
Tuesday
Thursday
Friday
Monday
Map fixed positions first: M is Wednesday. Since Q is 2 away from M, Q is either Sunday or Sunday/Monday. Use the O-R block immediately to fill gaps.
Map fixed positions first: M is Wednesday. Since Q is 2 away from M, Q is either Sunday or Sunday/Monday. Use the O-R block immediately to fill gaps.
Establish the Timeline
Days: Mon, Tue, Wed, Thu, Fri, Sat, Sun. Given: M=Wed. Q is two days from M, so Q is Sunday (Sun-Sat-Fri-Thu-Wed: M is Wed, Q is Sun (1) or Sun-Sat-Fri-Thu-Wed-Tue-Mon: M is Wed, Q is Mon (2)). If Q is Sunday, then 2 persons between M (Wed) and Q (Sun) is impossible. So Q is Monday (Mon, Tue, Wed).
Place O and R
O is immediately before R (O, R) and not on Thursday. Available slots: Tue, Thu, Fri, Sat. The only consecutive pair available is Fri-Sat. So O=Fri, R=Sat.
Place N, S and P
N and S have two persons between them. N is not on Sunday. Remaining days: Tue, Thu. If N=Tue, then S must be Fri (already occupied) or Sat (occupied). If N=Thu, two gaps lead to Mon (Q) or Sun (empty). This forces N=Thursday and S=Sunday. P fills the remaining day, which is Tuesday.
A: Monday is Q, B: Tuesday is P, C: Thursday is N, D: Friday is O.
B is correct because following all constraints (M=Wed, Q=Mon, O=Fri, R=Sat, N=Thu, S=Sun), P must occupy Tuesday.
In scheduling puzzles, always identify the 'anchor' (fixed day) first and test extreme possibilities for the person who has the most constraints.