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Seven boxes A, B, C, D, E, F and G are kept one over the other but not necessarily in the same order. C is not kept below G. Only five boxes are kept below E. Only one box is kept between C and E. B is kept above A but below G. F is not the topmost box. Which box is kept immediately below F?
B
D
C
E
C
Fix the anchor position first (the one with the most constraints like E) and place remaining boxes based on the relative gap conditions.
Fix the anchor position first (the one with the most constraints like E) and place remaining boxes based on the relative gap conditions.
Establishing the base order
There are 7 boxes. Only 5 boxes are below E, meaning E is at position 6 (from top=1 to bottom=7). Thus, the order is: 1:?, 2:?, 3:?, 4:?, 5:?, 6:E, 7:?
Applying distance constraints
Only one box is between C and E, and C is not below G (C must be above G). E is at 6, so C must be at position 4. Order: 1:?, 2:?, 3:?, 4:C, 5:?, 6:E, 7:?
Placing remaining boxes
B is between G and A (G > B > A). Remaining slots are 1, 2, 3, 5, 7. F is not the top box. If we place G at 1, B at 2, and A at 3, we have 5 and 7 left for D and F. Since F cannot be at 7 (implied by immediate below logic) or top, F goes to 5, leaving D at 7. Order: 1:G, 2:B, 3:A, 4:C, 5:F, 6:E, 7:D.
Identifying box below F
In the established sequence G, B, A, C, F, E, D, the box immediately below F is E.
A: B is at position 2, not below F. B: D is at position 7, which is below E, not F. D: E is actually the correct box found at position 6, immediately below F at position 5.
D is correct because based on the sequence G, B, A, C, F, E, D, the box E is placed immediately below F.
In box-stacking puzzles, always use a vertical numbering system from 1 (top) to N (bottom) to visualize gaps easily.