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Each of P, Q, R, S, T, U and V has an exam on a different day of a week starting from Monday and ending on Sunday of the same week. Q has the exam on Saturday. Only four people have exams after U. R has the exam immediately before T but not on Monday. S has the exam after P but before U. How many people have exams between R and V?
Three
Two
Five
Four
Two
Fix the fixed anchor (Q: Saturday), use the constraint 'four people after U' to place U (Tuesday), then fill R-T block and S-P-U sequence.
Fix the fixed anchor (Q: Saturday), use the constraint 'four people after U' to place U (Tuesday), then fill R-T block and S-P-U sequence.
Establish Fixed Points
Q is Saturday. 'Four people after U' means U is Tuesday (Wednesday, Thursday, Friday, Saturday are the 4 days after).
Positioning P, S, R, T
S is after P but before U, so P=Monday and S=Wednesday. R is before T, and R cannot be Monday, so the only remaining adjacent slots are Thursday and Friday for R and T.
Final Placement
Remaining person V goes to Sunday. Sequence: Monday-P, Tuesday-U, Wednesday-S, Thursday-R, Friday-T, Saturday-Q, Sunday-V. People between R (Thursday) and V (Sunday) are T and Q (2 people).
A: Incorrect; there are exactly two people between R and V, not three. C: Incorrect; five people would imply a different layout. D: Incorrect; four people is not consistent with the fixed constraints.
B is correct because the sequence P-U-S-R-T-Q-V places T and Q between R and V, totaling two people.
In scheduling puzzles, always identify the 'Anchor' (the element with a fixed day) first to minimize guesswork.
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