Identify the formula

The area of a regular hexagon with side length $s$ is given by the formula which represents the sum of areas of 6 equilateral triangles.

$\text{Area} = 6 \times \left( \frac{\sqrt{3}}{4} s^2 \right) = \frac{3\sqrt{3}}{2} s^2$

Substitute the side length

Given $s = 4$ cm, substitute this value into the area formula.

$\text{Area} = \frac{3\sqrt{3}}{2} \times (4)^2$

Calculate the final result

Perform the arithmetic: $4^2 = 16$. Then multiply: $\frac{3\sqrt{3}}{2} \times 16 = 3\sqrt{3} \times 8 = 24\sqrt{3}$.

$\text{Area} = 24\sqrt{3} \text{ cm}^2$