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H, I, J, L, M and N live on six different floors of the same building. The lowermost floor in the building is numbered 1, the floor above it is numbered 2 and so on, till the topmost floor, which is numbered 6. M lives on floor number 6. Only three people live between M and H. L lives on a floor below H. N lives on an even-numbered floor. I lives on an odd-numbered floor but not on floor number 5. How many people live between J and H?
One
Three
Two
Four
Two
Fix the anchor (M) and the constraint (three people between M and H) immediately to establish the skeleton of the building.
Fix the anchor (M) and the constraint (three people between M and H) immediately to establish the skeleton of the building.
Establish the Floors
Given M is on floor 6. Three people between M and H means H must be on floor 2 (6-1-1-1-1=2). Floor mapping: 6-M, 5-?, 4-?, 3-?, 2-H, 1-?.
Apply Constraints for L, N, and I
L lives below H, so L must be on floor 1. N is on an even floor; the remaining even floors are 4. Thus, N is on floor 4. I is on an odd floor but not 5, so I must be on floor 3. Remaining person J takes floor 5.
Final Arrangement and Verification
Final order from top to bottom: 6-M, 5-J, 4-N, 3-I, 2-H, 1-L. Between J (floor 5) and H (floor 2), there are two people: N and I.
A: One is incorrect as it ignores the two-person gap; B: Three is incorrect because only two people reside between floor 5 and 2; D: Four is incorrect as it exceeds the calculated gap between J and H.
C is correct because our logical deduction confirms that N (floor 4) and I (floor 3) are the two people living between J (floor 5) and H (floor 2).
In floor-based puzzles, always place the person with the most constraints first and use the remaining floors to satisfy negative constraints (like I not on floor 5).
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