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If 1 is added to each even digit and 2 is subtracted from each odd digit in the number 8439275, how many digits appear more than once in the new number?
1
2
3
0
2
Apply the given arithmetic rules digit by digit from left to right, then count the frequencies of the resulting digits to find which ones appear more than once.
Apply the given arithmetic rules digit by digit from left to right, then count the frequencies of the resulting digits to find which ones appear more than once.
Analyze the Original Number and Rules
The given number is 8439275. The specified rules are: add 1 to each even digit and subtract 2 from each odd digit.
Apply Transformation Digit by Digit
Processing each digit from left to right: 8 (even) becomes 9, 4 (even) becomes 5, 3 (odd) becomes 1, 9 (odd) becomes 7, 2 (even) becomes 3, 7 (odd) becomes 5, and 5 (odd) becomes 3. The new sequence is 9517353.
Count Digit Frequencies
In the new number 9517353, the digit 1 appears 1 time, 3 appears 2 times, 5 appears 2 times, 7 appears 1 time, and 9 appears 1 time. The digits that appear more than once are 3 and 5, giving a total of 2 digits.
A: 1 is incorrect because there are two repeated digits, not one. C: 3 is incorrect because only two digits repeat, not three. D: 0 is incorrect because digits 3 and 5 both appear twice.
B is correct because the transformed number is 9517353, where the digits 3 and 5 both appear twice, resulting in exactly 2 digits that appear more than once.
Always write out the complete transformed sequence and check digit counts systematically to avoid overlooking any repeated values.
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