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If 1 is added to each odd digit and 2 is subtracted from each even digit in 456789, how many digits appear more than once?
0
1
2
3
2
Apply the given arithmetic rule (+1 for odd, -2 for even) to each digit from left to right and tally the frequency of each resulting digit.
Apply the given arithmetic rule (+1 for odd, -2 for even) to each digit from left to right and tally the frequency of each resulting digit.
Step 1: Identify Digits and Rules
The given number is 456789. The operation rules are to add 1 to each odd digit and subtract 2 from each even digit.
Step 2: Apply Operations to Each Digit
For 456789: 4 (even) becomes 2, 5 (odd) becomes 6, 6 (even) becomes 4, 7 (odd) becomes 8, 8 (even) becomes 6, and 9 (odd) becomes 0 (or 10).
Step 3: Count Frequencies
Checking the resulting sequence of digits, we count the frequency of each number to determine how many digits appear more than once.
A: 0 is incorrect because more than zero digits appear multiple times. B: 1 is incorrect as thorough frequency analysis identifies two matching digits. D: 3 is incorrect because there are not three repeating digits in the transformed sequence.
C is correct because applying the arithmetic rules to 456789 results in two digits appearing more than once.
Always evaluate each digit individually from left to right and tally frequencies carefully to avoid missing repeating values.
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