Join 60,000+ competitive exam aspirants
or with email
Your Cart
SubtotalтВ╣0
TotalтВ╣0
Examoogle тАв User тАв info@examoogle.com тАв EE-2024-8821
Chapter 1 of 12 тАв Page 1 of 248ЁЯФТ Protected PDF тАв Watermarked
Join 60,000+ competitive exam aspirants
If C = { 2, 4, 6, 8, 10, 12, 14, 16 }, and D = {5, 10, 15, 20 }, then the number of elements in the set D - C is:
3
4
7
8
3
Mentally identify the common elements in both sets and subtract their count from the total number of elements in the first set mentioned in the difference operation.
Set C = {2, 4, 6, 8, 10, 12, 14, 16} and Set D = {5, 10, 15, 20}.
n(DтИТC)=n(D)тИТn(DтИйC)
Mentally identify the common elements in both sets and subtract their count from the total number of elements in the first set mentioned in the difference operation.
Students often calculate C - D instead of D - C, or forget to exclude elements that are present in set C from set D.
Identify intersection elements
Identify elements present in both sets D and C. Looking at sets, the common element is {10}.
DтИйC={10}
Perform set difference
To find D - C, remove all elements of set D that are also in set C. We take set D = {5, 10, 15, 20} and remove 10.
DтИТC={5,15,20}
Count the resulting elements
Count the number of elements in the resultant set {5, 15, 20}. There are 3 elements.
n(DтИТC)=3
A is correct because the set difference D - C results in {5, 15, 20}, which contains exactly 3 elements.
Set difference is similar to subtraction in arithmetic; always focus on removing common elements from the minuend set.
Get instant step-by-step AI explanations, full shift Previous Year Papers (SSC GD, RRB, SSC JE), and regional rank analysis on the official Examoogle App.
Free Download тАв 100K+ Aspirants