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If Iaβ is the positive sequence current of an alternator and Zβ, Zβ and Zβ are the sequence impedances of the alternator. The drop produced by the current Iaβ will be
IaβZβ
Iaβ (Zβ + Zβ)
Iaβ(Zβ + Zβ + Zβ)
Iaβ(Zβ + Zβ)
Ia1Z1
Quick Summary: Practice and solve "If Ia1 is the positive sequence current of an alternator and Z1, Z2 and Z0 are the sequence impedanc..." for Electrical - Power System. The correct answer is Option A: Ia1Z1. Detailed step-by-step solution, conceptual clarity, and formulas on Examoogle.
Answer:
Option **(a) **