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ElectricalBasic Electrical
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If maximum value of current is 100A, then average value is

A

50A

B

100A

C

0

D

63.7A

Correct Answer

тЪЩя╕П TE тАв Technical Direct FormulaElectricalBasic Electrical
Option D

63.7A

Quick Summary:

Given: Maximum value of alternating current ImI_{m}ImтАЛ = 100A

ЁЯУРMAMath SolutionDirect Formula
ЁЯУЛ Given

Maximum value of alternating current ImI_{m}ImтАЛ = 100A

ЁЯФв Formula Used

Iavg=2Im╧АI_{avg} = \frac{2 I_m}{\pi}IavgтАЛ=╧А2ImтАЛтАЛ

ЁЯУК Diagram / Illustration
I(t)=ImsinтБб(╧Йt)I(t) = I_m \sin(\omega t)I(t)=ImтАЛsin(╧Йt)
Half-cycle average: Iavg=0.637ImI_{avg} = 0.637 I_mIavgтАЛ=0.637ImтАЛ
ЁЯФв Step-by-Step Solution
1

Identify given values

The maximum value of the sinusoidal alternating current is given as Im=100AI_m = 100AImтАЛ=100A.

Im=100AI_m = 100AImтАЛ=100A

2

Select the average value formula

For a full sinusoidal waveform over a half-cycle, the average value is calculated using the relationship Iavg=2Im╧АI_{avg} = \frac{2I_m}{\pi}IavgтАЛ=╧А2ImтАЛтАЛ.

Iavg=2Im╧АI_{avg} = \frac{2 I_m}{\pi}IavgтАЛ=╧А2ImтАЛтАЛ

3

Substitute and solve

Substitute Im=100I_m = 100ImтАЛ=100 and ╧АтЙИ3.14159\pi \approx 3.14159╧АтЙИ3.14159 into the formula: Iavg=2├Ч1003.14159=2003.14159тЙИ63.66AI_{avg} = \frac{2 \times 100}{3.14159} = \frac{200}{3.14159} \approx 63.66AIavgтАЛ=3.141592├Ч100тАЛ=3.14159200тАЛтЙИ63.66A.

IavgтЙИ63.7AI_{avg} \approx 63.7AIavgтАЛтЙИ63.7A

тЬЕ

D is correct because the average value of a sinusoidal current over a half-cycle is defined as 2╧А\frac{2}{\pi}╧А2тАЛ times the maximum value, resulting in approximately 63.7A.

Core Concepts Used
Click any tag to open in AI Tutor
AC Fundamentals Average Current Sinusoidal Waveform
ЁЯТб EXAM TIP

Always distinguish between Average value (0.637Im0.637 I_m0.637ImтАЛ), RMS value (0.707Im0.707 I_m0.707ImтАЛ), and Peak-to-Peak value (2Im2 I_m2ImтАЛ) for AC circuits in electrical machines and power systems.

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