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If the distance between A and B is 1089 Km. From A, Vishal goes to B with speed 104 km/h and return to A with the speed 125 km/h. Find the average speed of Vishal. (rounded off to two decimal place)
111.79 km/h
113.54 km/h
117.44 km/h
120.89 km/h
113.54 km/h
Use the Harmonic Mean formula for average speed over equal distances. The distance 1089 km is irrelevant; the average depends only on the two speeds.
Distance between A and B = 1089 km, Speed from A to B (v1) = 104 km/h, Speed from B to A (v2) = 125 km/h.
AverageSpeed=v1тАЛ+v2тАЛ2├Чv1тАЛ├Чv2тАЛтАЛ
Use the Harmonic Mean formula for average speed over equal distances. The distance 1089 km is irrelevant; the average depends only on the two speeds.
Students often calculate the arithmetic mean (104 + 125) / 2 = 114.5, which is incorrect for average speed over equal distances.
Identify Given Values
Identify the two speeds for the equal distance commute.
v1тАЛ=104km/h,v2тАЛ=125km/h
Apply Average Speed Formula
Since the distance is the same for both journeys, use the Harmonic Mean formula.
AverageSpeed=104+1252├Ч104├Ч125тАЛ
Calculate Denominator
Sum the two given speeds.
104+125=229
Calculate Numerator
Multiply 2 by the two speeds.
2├Ч104├Ч125=26000
Final Division
Divide the numerator by the denominator and round to two decimal places.
AverageSpeed=22926000тАЛтЙИ113.5371...тЙИ113.54km/h
B is correct because the harmonic mean of 104 km/h and 125 km/h results in approximately 113.54 km/h.
This concept is fundamentally identical to finding the equivalent resistance of two resistors in parallel, where R = (2 * R1 * R2) / (R1 + R2) is not directly applicable, but the inverse logic (1/RavgтАЛ = 1/2(1/v1 + 1/v2)) mirrors parallel circuitry.