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If the interest earned during the 2nd year on a certain sum is ₹3726, and the rate of interest is 15% per annum compounded annually, then the sum is:
₹21600
₹20885
₹21185
₹20835
₹21600
Use the fact that interest in the 2nd year is the interest on (Principal + interest of 1st year). Specifically, Interest2nd=P×(1.15)×0.15=3726. Solve for P = 3726 / (1.15 × 0.15).
Interest earned in the 2nd year = ₹3726, Rate of interest (R) = 15% per annum, Time = 2 years.
Interest2nd=P×(1+100R)×100R
Use the fact that interest in the 2nd year is the interest on (Principal + interest of 1st year). Specifically, Interest2nd=P×(1.15)×0.15=3726. Solve for P = 3726 / (1.15 × 0.15).
Many students calculate the simple interest for two years or apply the Compound Interest formula for 2 years (A - P) without isolating the 2nd year specifically.
Define the relationship
The interest earned in the second year is the compound interest on the amount at the end of the first year for one more year. If P is the principal, the amount after 1 year is P(1+R/100). The interest for the 2nd year is this amount multiplied by the rate.
I2=P(1+100R)×100R
Substitute given values
Substitute I2=3726 and R=15. The expression becomes 3726=P(1+0.15)×0.15.
3726=P(1.15)(0.15)
Calculate the Principal
Simplify the equation: 3726=P×0.1725. Solving for P: P=3726/0.1725=21600.
P=0.17253726=21600
A is correct because the principal amount calculated using the interest of the second year specifically is ₹21600.
This concept is vital for 'Installment' problems in banking exams, where the value of an installment is effectively the interest plus partial principal payment.